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stiv31 [10]
4 years ago
15

What is chromatography?

Chemistry
1 answer:
Lunna [17]4 years ago
5 0
The separation of a mixture by passing it in solution through a medium in which the components move at different rates

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Why is the wavelength of 633 nm used to analyze the standard solutions and drink samples?
DanielleElmas [232]

Answer:

The correct option is;

A. Corresponding with orange light, is the wavelength that blue solutions absorb the most

Explanation:

The wavelength of 633 nm is the wavelength of red light emitted by the helium-neon laser also known as the He-Ne laser

According to absorption spectroscopy and the color wheel, a solution or drink sample that is efficient at absorbing light having a wavelength of 633 nm will appear blue, because, light at 633 nm is red and very close to orange which is the complementary color blue light.

4 0
3 years ago
2-Ethoxy-2,3-dimethylbutane reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction
Leno4ka [110]

Answer:

A = 2-iodo-2,3-dimethylbutane

B = Ethanol

C = Iodoethane (also called ethyl-iodide)

Explanation:

2-Ethoxy-2,3-dimethylbutane reacts with conc. HI to cleave the oxy-functional group.

On one end, ethanol is formed and on the other hand, 2-iodo-2,3-dimethylbutane is formed.

But ethanol reacts further with conc HI to give iodoethane.

Therefore,

A = 2-iodo-2,3-dimethylbutane

B = Ethanol

C = Iodoethane (also called ethyl-iodide)

This is all shown in the attached image.

Hope this Helps!!!

6 0
4 years ago
I REALLY NEED HELP
Rashid [163]
1. <span>number of electrons
2.Si
3.Cu
4.There are three positively charged proton in the nucleus
5.mass number
6. A physical substance occur in A and a chemical change occur in B
7.53
8. dont know what you talking about.sorry
9. Independent variable
10.7.5g
This is an answer I can come up with.</span>
7 0
3 years ago
Isº2s2p 3sº3p®45*3d"4p^5s*4d"5p<br> 6s4f5d"6p
solniwko [45]

Answer:

gibberish

Explanation:

its literaly nothing _#_$&_θГ[§θμθ_(;!&#\=&.·&:ГГ:¬¬&μ!¬´€

4 0
3 years ago
In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)20) + 2 NaBr jaPbBr2s 2 NaNO3a) The mo
Shtirlitz [24]
<span> Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
                     2 mol                             2 mol

M(NaBr)= 102 g/mol
M(NaNO3) = 85 g/mol

1) 244g NaNO3 *1 mol NaNO3/85 g NaNO3 = 244/85 mol NaNO3

2)</span> Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
                     2 mol                             2 mol<span>
                     x mol                             </span>244/85 mol 
<span>
x=(2 mol*</span> 244/85 mol )/2 mol =  244/85 mol NaBr
<span>
3) </span> 244/85 mol NaBr*102g NaBr/1 mol = (244*102/85) g NaBr =292.8 g NaBr<span>
              

</span>
8 0
3 years ago
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