Answer:
1 joule = 0.737 foot-pound
Joule is the unit of work.
1 J = 1 N·m
In SI units
1 J = 1 kg· m/s²
0.737 foot-pound is the amount of work to raise 0.737 pounds one foot or raising one pound to 0.737 ft.
Answer:
About 7.5 years
Explanation:
The orbital period is proportional to the semimajor axis raised to the power of 3/2.
The orbital period is <em>also</em> inversely proportional to the square root of the sum of the masses of the sun and the asteroid; however, the sun's mass is a constant and the asteroid's mass is negligible in comparison with the sun's mass.
Answer:
by doing the test over and over again until you get the right results
Explanation:
The Correct answer to this question for Penn Foster Students is: 214.4 J
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
