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3 years ago

Although planets orbit the Sun in ellipses, all the planetary orbits are fairly close to circular and not very eccentric.

Physics

1 answer:

Nutka1998 [239]3 years ago

8 0

Answer:

False

Explanation:

The Sun rotates in this same, right-hand-rule direction. All planetary orbits lie in nearly the same plane. All planetary orbits are nearly circular (eccentricity near zero).

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A uniformly charged sphere has a total charge of 300uc and a radius of 8cm. Find the electric field density at A point 16cm from

s2008m [1.1K]

E = kQ 

(r + h)²

where,

k = 9 × 10^9Nm²C^-2

Q = total charge, 300uC = 300 × 10^ -6C

r = 8 × 10^ -2m

h = 16 × 10^ -2m

then,

E = 9e9 * 300e^-6 

(8e^-2 + 16e^-2)²

E = 4687500N/C

6 0

3 years ago

Below is an oscilloscope trace from an AC supply. Calculate the frequency of the supply if each horizontal division represents 0

GuDViN [60]

Answer:

20 hertz of frequency produced.

Explanation:

$\boxed{frequency = \frac{1}{period} }$

Here we will find frequency and period should be in second, here given: 0.05 seconds

using the formula:

$\boxed{frequency = \frac{1}{0.05} }$

$\boxed{frequency =20}$

8 0

3 years ago

One of the important waste products of photosynthesis is oxygen gas. Where does this oxygen gas come from?

chubhunter [2.5K]

Answer:

End product of photosynthesis.

Explanation:

Photosynthesis is a process that plants undergo in the manufacture of their food. This is done in the presence of sunlight which is trapped by their coloring pigment called chlorophyll and reactants such as Carbon dioxide and Water.

6CO2+6H2O= C6H12O6+ 6O2

The oxygen gas which is a waste product of photosynthesis is released into the atmosphere and used by animals in respiration.

5 0

3 years ago

Read 2 more answers

What is the voltage of the electrochemical cell written as: Cu(s) | Cu2+(aq) || Mg2+(aq) | Mg(s)?

erma4kov [3.2K]

Thank you for posting your question here at brainly. Feel free to ask more questions.
The best and most correct answer among the choices provided by the question is B.-2.71 V.
Mg2+(aq) + 2e- -> Mg(s) E=-2.37 V

Cu2+(aq) + 2e- -> Cu(s) E =+ 0.34 V

Since Cu is acting as the anode, the equation needs to be reversed.

Cu(s) -> Cu2+(aq) + 2e- E =- 0.34 V

Ecell= -2.37 V+ (- 0.34 V) = -2.71 V 

Hope my answer would be a great help for you.

4 0

4 years ago

Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87

marshall27 [118]

Answer:

a) $\lambda=0.935\ \textup{m}$