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olga nikolaevna [1]
3 years ago
15

Kim took 5 hours to complete a journey with an average speed of 80 km/h. For the first 3 hours, she travelled at an average spee

d of 60km/h. What was her average speed for the remaining time of the journey ?
Physics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:110

Explanation:

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Analyze how friction can be both a positive and negative aspect on our lives
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Positive - Friction allows us to create heat in a desperate situation, like being lost in the woods. If we didn't have friction, we would probably freeze to death.
Negative - Friction can also cause unwanted fires, such as forest fires. If friction didn't exist, we wouldn't have these.
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4 years ago
What is the weight of a dog that has a mass of 47.0 kg?​
Nat2105 [25]

Answer:

while we often confuse mass with weight, 47 kg is 47 x 9.8 = 460.6 Newtons. 9.8 is acceleration of gravity in m/sec/sec

8 0
3 years ago
An automobile with a mass of 1180 kg is traveling at a speed v = [06] ____________________ m/s. a. What is its kinetic energy in
iogann1982 [59]

Complete Question:

An automobile with a mass of 1180 kg is traveling at a speed v =2.51 m/s. What is its kinetic energy in SI units? What speed (m/s) must an 82.7-kg person move to have the same kinetic energy? At what speed (m/s) must is 12.1-g bullet move to have the same kinetic energy? What would be the speed (m/s) of the automobile if its kinetic energy were doubled?

Answer:

a) 3717.1 J b) 9.48 m/s c) 783.8 m/s d) 3.55 m/s

Explanation:

a)

  • By definition, the kinetic energy of a mass m with a speed v, is as follows:

      K = \frac{1}{2} * m *v^{2}

  • if m= 1180 Kg, and v= 2.51 m/s, the kinetic energy can be calculated as follows:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*(2.51 m/s)^{2} = 3717.1 J

b)

  • If the kinetic energy must be the same, and m= 82,7 Kg, we can write the following expression:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 82.7 kg*((v)(m/s))^{2} = 3717.1 J

  • We can solve the above equation as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{82.7kg} } = 9.48 m/s

c)

  • If K remains the same, and m = 12.1 g = 0.0121 kg (in SI units). we can solve for v  as follows:

       v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{0.0121kg} } = 783.8 m/s

d)

  • Now, if the kinetic energy were doubled, we would have the following equation:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*((v) m/s)^{2} = 3717.1 J * 2 = 7434.2 J

  • We can solve for the new speed v as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*7434.2J}{1180kg} } = 3.55 m/s

8 0
3 years ago
A. Ice caps and glaciers <br> B. Rivers and Lakes <br> C. Groundwater
mariarad [96]

Answer:

It is A i think

Explanation:

8 0
3 years ago
An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance
Ipatiy [6.2K]

Answer:

Distance s  = 90 meter

Explanation:

Given:

Initial velocity u = 0 m/s

Final velocity v = 30 m/s

Acceleration a = 5 m/s²

Find:

Distance s

Computation:

v² = u² + 2as

30² = 0² + 2(5)(s)

Distance s  = 90 meter

5 0
3 years ago
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