Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
Answer:
Ur answer is Stationary Front
Explanation:
Stationary Front is when a cold air mass and a warm air mass but are at a standstill the boundary is called Stationary Front.
Answer:
Electrical resistivity and its inverse, electrical conductivity, is a fundamental property of a material that quantifies how strongly it resists or conducts electric current. A low resistivity indicates a material that readily allows electric current. Resistivity is commonly represented by the Greek letter ρ.
Answer:
(a) Acceleration of the bag will be a=16.214m/sec^2
(B) Weight of the bag will be 137.2 N
Explanation:
We have given mass of the bag m = 14 kg
Force with which bag is lifted = 227 N
(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration
So 
(b) Acceleration due to gravity 
We know that weight is given by W = mg , here m is mass and g is acceleration due to gravity
So weight 
So weight of the bag will be 137.2 N
