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aksik [14]
3 years ago
5

A bowling ball hits two standing bowling pins at the same time. Which of the following is true? Assume that all collisions are e

lastic. A. The sum of the momentum of both pins after the collision will equal the momentum of the ball before the collision. B. The momentum of the ball after the collision will equal the momentum of the ball before the collision. C. The sum of the momentum gained by both pins will equal the amount of momentum lost by the ball. D. The momentum of each pin after the collision will equal the momentum of the ball before the collision.
Physics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

C. The sum of the momentum gained by both pins will equal the amount of momentum lost by the ball.

Explanation:

The law of conservation of momentum states that total momentum before collision must be equal to the total momentum after collision.

Momentum could be transferred from one object to another during collision. When the ball hits the stationary pins, momentum is transferred from the ball to the pins.

Since the collision is elastic, momentum is conserved hence total momentum gained by the pins equals the total momentum lost by the ball.

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The best and most correct answer among the choices provided by your question is the third choice or letter C.
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</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
Consider electromagnetic waves in free space. What is the wavelength of a wave that has the following frequencies? (a) 4.10 x 10
navik [9.2K]

Explanation:

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7 0
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Correct the following statement:
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Answer:

It's the 3rd option

Explanation:

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4 0
3 years ago
A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan
ASHA 777 [7]

Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of a \;\;m/s^2 from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

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As acceleration, a=\frac{v-u}{t}=\frac{5-4.2}{t}

\Rightarrow at=0.8\cdots(i)

Now, from the equation of motion

s=ut+\frac 12 at^2

\Rightarrow s=ut+\frac 12 at(t)

\Rightarrow 115=4.2t+\frac 12 \times 0.8 t [ from equation (i)]

\Rightarrow 115=(4.2+0.4)t

\Rightarrow t= 115/4.6 = 25 seconds.

Hence, she takes 25 seconds to walk the distance.

5 0
3 years ago
a motorcycle is capable of accelerating at 5.1 m/s starting from rest how far can it travell in 1.5 sec
Katarina [22]
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Plugging in our known values, we have

<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>

5 0
3 years ago
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