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3 years ago

Describe the day of June 21 at the North Pole in terms of daylight and darkness ( science )

1 answer:

7 0

On June 21, as seen from the North pole ...

-- the sun has been up, and it's been light outside,
for the past three months ... ever since March 21 .

-- The sun won't set, and it won't be dark outside,
for another three months ... until September 21.

-- Here at the North pole, it stays daylight for six months straight.
Today, on June 21, we're exactly halfway through the period of
continuous daylight.

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Can someone help me please

kap26 [50]

(3 x 10^10 Hg) x (1 mole Hg/6.022 x 10^23 Hg) x (200.59g / 1 mole Hg) =
99.928 x 10^-13
10^-9 g Hg x (1 mole Hg / 200.59 g Hg) x (6.022 x 10^23 Hg / 1 mole Hg) =
0.031 x 10^14 Hg = 3.1 x 10^12 Hg
I.) 10^-11 g Hg
II.) 3.1 x 10^12 Hg

4 0

2 years ago

Aqueous solutions of copper (II) bromide and silver (1) acetate react to form solid

Sladkaya [172]

Answer:

5.63 g

Explanation:

Step 1: Write the balanced equation

CuBr₂(aq) + 2 AgCH₃CO₂(aq) ⇒ 2 AgBr(s) + Cu(CH₃CO₂)₂(aq)

Step 2: Calculate the reacting moles of copper (II) bromide

30.0 mL of 0.499 M CuBr₂ react. The reacting moles of CuBr₂ are:

$0.0300L \times \frac{0.499mol}{L} = 0.0150mol$

Step 3: Calculate the moles formed of silver (I) bromide

The molar ratio of CuBr₂ to AgBr is 1:2. The moles formed of AgBr are 2/1 × 0.0150 mol = 0.0300 mol.

Step 4: Calculate the mass corresponding to 0.0300 mol of AgBr

The molar mass of AgBr is 187.77 g/mol.

$0.0300 mol \times \frac{187.77g}{mol} = 5.63 g$

4 0

3 years ago

Light travels at a rate of 3.00 x 10^8 m/s. It takes light 8.30 min to travel from the surface of the sun to the earth. What is

bija089 [108]

Answer: The distance of the earth from the sun is $1.494\times 10^{11}m$

Explanation:

Speed of light = $3.00\times 10 ^8 m/s$

Time taken to travel from sun to earth = 8.30 mins = $8.3\times 60=498sec$ (1min=60 s)

As we know ; Speed is defined as the distance travelled per unit time.

$Distance=speed\times time$

Hence distance between sun and earth = $3.00\times 10^8m/s\times 498s=1.494\times 10^{11}m$

Thus the distance of the earth from the sun is $1.494\times 10^{11}m$

7 0

3 years ago

if, on average a person drinks eight glasses of water each day, and each glass contains 300 mL. a. how many liters of water will

yulyashka [42]

A.)

300 ml * 8 = 2.4 gallons a day.

now time to see how much a year..

2.4 * 365 = 876 liters

B.)

one liter = 2.2 pounds

876 x 2.2 = 1927.2 pounds

Answers:

<u>A.) 2.4 * 365 = 876 liters</u>

<u>B.) 876 x 2.2 = 1927.2 pounds</u>

5 0

2 years ago

Density measurements were conducted on a 22.5oC sample of water which had a theoretical density of 0.997655 g/ml. A volume of 10

Sophie [7]

Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).

(1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:

$p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL$

(2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):

$p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3} \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL$

(3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:

%error= $\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100$

%error= $\frac{|1.022g/mL-0.997655g/mL|}{0.997655g/mL}*100$

%error=2.44 %

7 0

3 years ago