Question

What is the density of ammonia (NH3) at 273 K and 1.00 atm? 0.7601 g/L 0.982 g/L 1.23 g/L 2.43 g/L

Answer 1

Answer:The density of ammonia ($NH_3$) at 273 K and 1.00 atm is 0.75 g/L.

Explanation:

Temperature of the gas = T = 273 k

Pressure exerted by the gas,P = 1.00 atm

Volume occupied by the gas = V

Number of  moles of gas = n

PV=nRT (Ideal gas equation)

$PV=\frac{\text{Mass of ammonia gas}}{\text{Molar mass of the ammonia}}$

$\frac{P\times \text{Molar mass of ammonia}}{RT}=\frac{\text{Mass of ammonia gas}}{V}=\text{Density of the gas}$

Density of the gas:

$\frac{1 atm\times 17 g/mol}{0.0820 L atm\mol K\times 273 K}=0.75 g/L$

The density of ammonia ($NH_3$) at 273 K and 1.00 atm is 0.75 g/L.