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MaRussiya [10]
3 years ago
11

What is made up of usable amounts of metallic elements

Chemistry
2 answers:
posledela3 years ago
8 0

<span>A </span>metal<span> is a material (an </span>element<span>, </span>compound<span>, or </span>alloy<span>) that is typically hard, opaque, shiny, and has good </span>electrical<span> <span>and </span></span>thermal conductivity<span>. Metals are generally </span>malleable<span> <span>— that is, they can be hammered or pressed permanently out of shape without breaking or cracking — as well as </span></span>fusible<span> <span>(able to be fused or melted) and </span></span>ductile<span> (able to be drawn out into a thin wire). About 91 of the 118 elements in the </span>periodic table<span> <span>are metals, the others are </span></span>nonmetals<span> <span>or </span></span>metalloids<span>. Some elements appear in both metallic and non-metallic forms.</span>

Solnce55 [7]3 years ago
3 0


The choices are:

Carbonate


ore


silicate

a mineral

The correct option is:

ore
Explanation:

An ore is an experience of rock or sediment that comprises sufficient minerals with economically valuable elements, typically metals, that can be economically derived from the deposit. The ores are obtained from the earth through mining; they are then polished (often via smelting) to extract the important element or elements.A metal is a material (an element, compound, or alloy) that is typically hard, opaque, shiny, and has good electrical and thermal conductivity.


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AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

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Answer:

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