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Flauer [41]
3 years ago
14

Colour walked the distance of 50 miles in six hours workout Collins average speed give your answer in miles per hour

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

Collins walked an average of 8.3 miles per hour

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−6+3(2+(−4t)) using distributive property
Hatshy [7]

Answer:

- 6 + 3(2 +( - 4t)) \\  - 6 + 3(2 - 4t) \\  - 6 + 3(2t) \\  - 6 + 6t \\ t

4 0
3 years ago
Use completing the square to solve (x + 7)(x – 9) = 25 for x.
Finger [1]
We need to solve for x by completing the square of the given mathematical expression (x+7)(x-9) = 25.
First, we need to perform multiplication of (x+7) and (x-9) such as the expression become:
(x+7) (x-9) = 25
x² -9x +7x -63 = 25
x² - 2x = 25 + 63
Then perform addition of constant values 25 and 63
x² - 2x =88
Add +1 in both sides to complete the expression such as:
x² - 2x +1 = 88 +1
(x-1)(x-1) = 89
(x-1)² = 89
We see that (x-1) is a perfect square, we can now solve for the value of x such as:
(x-1) = +-√89
x1 = +√89  + 1
x1 = 10.4
x2 = -√89 +1
x2 = -8.4

The answers are 10.4 and -8.4.
3 0
3 years ago
Read 2 more answers
Which of the following is true regarding the sequence graphed below?
Mars2501 [29]

Answer:

where is the graph

Step-by-step explanation:

5 0
3 years ago
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2. Write 1.68 as a simplified fraction
Alex787 [66]
  • <em><u>1  \frac{68}{100 }</u></em>
5 0
3 years ago
When the width of a rectangle with a length of 3/5 foot was decreased by 1/3 foot, the area of the rectangle became 7/25. Find t
insens350 [35]

Answer:

\large\boxed{\text{The original width}\ =\dfrac{4}{5}\ ft}

Step-by-step explanation:

\text{The dimensions of rectangle:}\ \dfrac{3}{5}\times w.\\\\\text{The dimensions of new rectangel:}\ \dfrac{3}{5}\times\left(w-\dfrac{1}{3}\right)\\\\\text{The area of the new rectangle:}\ A=\dfrac{7}{25}\ ft^2\\\\\text{We have the equation:}\\\\\dfrac{3}{5}\left(w-\dfrac{1}{3}\right)=\dfrac{7}{25}\qquad\text{multiply both sides by 25}\\\\25\!\!\!\!\!\diagup^5\cdot\dfrac{3}{5\!\!\!\!\diagup_1}\left(w-\dfrac{1}{3}\right)=25\!\!\!\!\!\diagup^1\cdot\dfrac{7}{25\!\!\!\!\!\diagup_1}

15\left(w-\dfrac{1}{3}\right)=7\qquad\text{use the distributive property}\\\\15w-15\!\!\!\!\!\diagup^5\cdot\dfrac{1}{3\!\!\!\!\diagup_1}=7\\\\15w-5=7\qquad\text{add 5 to both sides}\\\\15w=12\qquad\text{divide both sides by 15}\\\\w=\dfrac{12:3}{15:3}\\\\w=\dfrac{4}{5}

5 0
3 years ago
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