All categories

3 years ago

Diamond is an allotrope of :

Chemistry

2 answers:

stepan [7]3 years ago

6 0

Answer:

Carbon

Explanation:

its literaly carbon

Marat540 [252]3 years ago

5 0

Answer:

carbon

Explanation:

because it is an allotrope of carbon

You might be interested in

It is expected that a chemical reaction will occur when copper metal is combined with aqueous zinc sulfate. Explain why there wi

REY [17]

Answer:

$E_{cell}$ = +ve, reaction is spontaneous

$E_{cell}$ = -ve, reaction is non spontaneous

$E_{cell}$ = 0, reaction is in equilibrium

Case 1: when copper metal is combined with aqueous zinc sulfate.

$Cu+ZnSO_4\rightarrow Zn+CuSO_4$

Here copper is undergoing oxidation ad thus acts as anode and zinc is undergoing reduction , thus acts as cathode.

$E^o_{cell}$ = standard electrode potential = $E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Cu^{2+}/Cu]}= +0.34V$

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Cu^{2+}/Cu]}$

$E^0=-0.76-(+0.34)=-1.10V$

Thus as $E_{cell}$ is negative , the reaction is non spontaneous.

Case 2: when zinc metal and aqueous copper sulfate solution are combined.

$Zn+CuSO_4\rightarrow Cu+ZnSO_4$

Here zinc is undergoing oxidation ad thus acts as anode and copper is undergoing reduction , thus acts as cathode.

$E^o_{cell}$ = standard electrode potential = $E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Cu^{2+}/Cu]}= +0.34V$

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Zn^{2+}/Zn]}$

$E^0=+0.34-(-0.76)=+1.10V$

Thus as $E_{cell}$ is positive , the reaction is spontaneous.

3 0

4 years ago

If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, which element is the reactant in excess? 3H2 +

kicyunya [14]

Answer:

nitrogen

Explanation:

The stoichiometry of the reaction says that $H_{2}$ and $N_{2}$ react 3:1 to form 2 moles of $NH_{3}$ , so, if you have 3,5 moles of H, which is equal to 1,75 moles of $H_{2}$ , and 5 moles of N, which are equal to 2,5 moles of $n_{2}$ . only $\frac{1,75 moles of H2}{3}$ =0.583 moles of $N_{2}$ , will react, leaving 1.917 moles of $N_{2}$ unreacted, and forming 0.583*2=1.166 moles of $NH_{3}$

3 0

3 years ago

Which diagram represents an object at static equilibrium?

Marianna [84]

The absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.

4 0

3 years ago

Read 2 more answers

Consider the following molecule. 1. How many bonding pair of electrons are present?

Artemon [7]

Answer:

There are 3 bonding pairs of electrons

Explanation:

For every bond there is one bonded pair of electrons. NH₃ has three N-H bonds, so has three bonding pairs of electrons along with a lone pair of electrons

5 0

3 years ago

Question 6: Describe an experiment for determining the position in the reactivity series for

Aleonysh [2.5K]

Answer: BI

because of rection progress

Explanation:

8 0

3 years ago