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EleoNora [17]
2 years ago
7

Katie swings a ball around her head at constant speed in a horizontal circle with circumference 2.1 m. What is the work done on

the ball by the 34.4 N tension force in the string during one half-revolution of the ball
Physics
1 answer:
Lady bird [3.3K]2 years ago
7 0

Answer:

the work done on the ball is 0

Explanation:

Given the data in the question;

Katie swings a ball around her head at constant speed in a horizontal circle with circumference 2.1 m.

circle circumference = 2πr = 2.1 m

radius r will be; r = 2.1 m / 2π = 0.33 m

Tension force = 34.4 N

one half revolution means, displacement of the ball is;

d = 2r = 2 × 0.33 = 0.66 m

Now, Work done = force × displacement × cosθ

we know that, the angle between the tension force on string and displacement of object is always 90.

so we substitute

Work done = 34.4 N × 0.66 m × cos(90)

Work done = 34.4 N × 0.66 m × 0

Work done = 0 J

Therefore,  the work done on the ball is 0

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Explanation:

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Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

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Therefore,

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Vi = √(1960 m²/s²)

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Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

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