<u>Answer:</u>
<em>4.5 L water we have in litres (L).</em>
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<u>Explanation:</u>

where
= Final T - Initial T
Q is the heat energy in calories
c is the specific heat capacity (for water 1.0 cal/(g℃))
m is the mass of water
Plugging in the values

So,
Volume of water = mass/density

=4.5 L (Answer)
Answer:
82.97 K
Explanation:
Applying,
PV/T = P'V'/T'................ Equation 1
Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
Make T' the subject of formula in equation 1
T' = P'V'T/PV................ Equation 2
From the question,
Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L
Substitute these values into equation 2
T' = (0.327×10.41×222.2)/(1.154×7.9)
T' = 82.97 K
Hence the new temperature is 82.97 K
dilution
V₁M₁=V₂M₂
V₁.12 = 100.6
V₁=50 ml
Add water 50 ml to 50 ml 12 M