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3 years ago

Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain.

Chemistry

1 answer:

Strike441 [17]3 years ago

8 0

Answer:

Option a.

0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i

Explanation:

To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)

These are the colligative properties:

ΔP = P° . Xm . i → Lowering vapor pressure

ΔT = Kb . m . i → Boiling point elevation

ΔT = Kf . m . i → Freezing point depression

π = M . R . T → Osmotic pressure

Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.

CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:

CaCl₂ → Ca²⁺ + 2Cl⁻

We have 1 mol of Ca²⁺ and 2 chlorides, so 3 moles of ions → i = 3

KNO₃ → K⁺ + NO₃⁻

We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2

Option a, is the best.

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An atom's Lewis dot structure has four dots. Which of the following elements could it be, and why?

Elis [28]

Answer:

Beryllium, because it is in period 2 and has four total electrons.

Explanation:

7 0

3 years ago

Suppose you are titrating vinegar, which is an acetic acid solution

kotegsom [21]

Answer:

0.373 M

Explanation:

The balanced equation for the reaction is given below:

HC2H3O2 + NaOH —> NaC2H3O2 + H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid, HC2H3O2 (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, we shall write out the data obtained from the question. This include:

Volume of base, NaOH (Vb) = 32.17 mL

Molarity of base, NaOH (Mb) = 0.116 M

Volume of acid, HC2H3O2 (Va) = 10 mL

Molarity of acid, HC2H3O2 (Ma) =..?

The molarity of the acid solution can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 10 / 0.116 x 32.17 = 1

Cross multiply

Ma x 10 = 0.116 x 32.17

Divide both side by 10

Ma = (0.116 x 32.17) /10

Ma = 0.373 M

Therefore, the concentration of the acetic acid is 0.373 M.

8 0

3 years ago

what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water fro

blsea [12.9K]

Answer:

10425 J are required

Explanation:

assuming that the water is entirely at liquid state at the beginning , the amount required is

Q= m*c*(T final - T initial)

where

m= mass of water = 25 g

T final = final temperature of water = 100°C

T initial= initial temperature of water = 0°C

c= specific heat capacities of water = 1 cal /g°C= 4.186 J/g°C ( we assume that is constant during the entire temperature range)

Q= heat required

therefore

Q= m*c*(T final - T initial)= 25 g * 4.186 J/g°C * (100°C- 0°C) = 10425 J

thus 10425 J are required

7 0

4 years ago

* The cost of table salt and table sugar is Rs 15 per kg.

Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

$\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878$

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

$\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63$

6 0

2 years ago

Identify the four parts of the potential energy diagram

Leni [432]

Answer:

Reactants, Activation energy, Energy released by the reaction and Products

Explanation:

This energy profile is that of an exothermic reaction. In an exothermic reaction, heat is liberated to the surrounding. The surrounding becomes hotter than the environment.

The first box to the left is the reactants which signifies the species combining together.

The topmost box is the activation energy which is the energy barrier that must be over come before a reaction takes place.

The box underneath is the energy change. Here, energy is being released.

The right most box is the product of the reaction.

4 0

2 years ago