<span>Oxygen has 8 protons in its nucleus. </span>
Answer:
1 gramo de metano aporta 50.125 kilojoules.
1 gramo de metano aporta 48.246 kilojoules.
Explanation:
La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (), en kilojoules por mol, dividido por su masa molar (), en gramos por mol:
(1)
A continuación, analizamos cada caso:
Metano
1 gramo de metano aporta 50.125 kilojoules.
Octano
1 gramo de metano aporta 48.246 kilojoules.
Answer:
I think probably diet because the type of food you put in your body (if it has high calorie or sodium) can severley affect your overall health and therefore affect your bpm(beats per minute)
Explanation:
Hey there! Hello!
Not sure if you still need the answer to this question, but I'd love to help out if you do.
So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2.
But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:
Left:
H: 2
O: 2
Right:
H: 2
O: 1
So we have to multiply H2O on the right side by 2 in order to get this:
Left:
H: 2
O: 2
Right:
H: 4
O: 2
The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:
Left:
H: 4
O: 2
Right:
H: 4
O: 2
That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)
Answer:
The balloon will occupy a volume of 6.48 L
Explanation:
<u>Step 1: </u>Data given
internal pressure = 1.00 atm
volume = 4.50 L
Temperature = 20.0 °C
<u>Step 2:</u> Calculate new volume via the ideal gas law
P*V = n*R*T
(P1*V1)/ T1 = (P2*V2)/T2
⇒ with P1 = 1.00 atm
⇒ with V1 = 4.50 L
⇒ with T1 = 20.0 °C = 293 Kelvin
⇒ with P2 = 0.600 atm
⇒ with V2 = TO BE DETERMINED
⇒ with T2 = -20°C = 253 Kelvin
(1.00atm * 4.50 L)/293 Kelvin = (0.600 atm*V2) / 253 Kelvin
0.01536 = 0.00237 V2
V2 = 6.48 L
The balloon will occupy a volume of 6.48 L