The height of the rail on top of the press box where the ball was dropped from is 11.025 m.
The given parameters:
- Time of motion of the ball, t = 1.5 s
- Let the height of the rail = h
<h3>Maximum height of fall;</h3>
- The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.
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Answer:
Hello,
The answer would be the first choice, "They both include a question, procedure and conclusion."
The velocity of penguin as he ends where he started was 0 m/s.
<h3>What is displacement?</h3>
Displacement is the length of straight line joining the initial and final position of the body.
Given is a penguin who waddled 8 m uphill before sliding back down to its friends in 2 seconds.
We know that the velocity is the rate of change of displacement with respect to time. Mathematically -
v = dx/dt
dx = v dt
∫dx = ∫v dt
Δx = vΔt
v = Δx/Δt
Now, the displacement of the penguin will be = Δx = 8 - 8 = 0
Then, its velocity will be -
v = 0/Δt = 0
Therefore, the velocity of penguin as he ends where he started was 0 m/s.
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Answer:
3.67 m
Explanation:
A physical quantity is said to be vector quantity if it need a magnitude as well as direction for complete explanation.
It makes an angle 23.5 degree from positive X axis.
So, it's component along X axis is given by
bx = B Cos theta
bx = 4 × Cos 23.5
bx = 3.67 m