Answer:
The average force the golf club exerts on the ball is 600 N
Explanation:
Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced
F = m× (v₂ - v₁)/(Δt)
The given parameters of the motion of the ball are;
The mass of the ball, m = 45 g = 0.045 kg
The initial velocity of the ball, v₁ = 0 m/s
The speed with which the ball was hit by the golfer, v₂ = 40 m/s
The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)
By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;
F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N
The average force the golf club exerts on the ball = F = 600 N.
So to find the mass we must use the formula D=M/V but because we don’t have the mass, we must use the formula M=DxV
So to find volume, just multiple the length (0.4m) width (0.4m) and height (2m) and you will get 0.32m as the volume. Now multiple this volume with your given density of 2,400 kg/m and you will get 768 kg as the mass of the marble block.
Final answer: 768 kilograms (kg) as mass of the marble block.
Examples of such quantities include distance, displacement, speed, velocity, acceleration, force, mass, momentum, energy, work, power, etc. All these quantities can by divided into two categories - vectors and scalars. A vector quantity is a quantity that is fully described by both magnitude and direction.
Answer:
Explanation:
Answer:
4.53 kg
Explanation:
spring constant, K = 16 N/m
Amplitude, A = 20 cm = 0.2 m
Maximum speed, v = 37.6 cm/s = 0.376 m/s
The formula for maximum speed is given by
v = ωA
where, ω is the angular frequency
0.376 = ω x 0.2
ω = 1.88 rad/s
m = 4.53 kg
Thus, the mass of banana bunch is 4.53 kg.
Answer:
The Milky Way is about 1,000,000,000,000,000,000 km (about 100,000 light years or about 30 kpc) across. The Sun does not lie near the center of our Galaxy. It lies about 8 kpc from the center on what is known as the Orion Arm of the Milky Way
