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Lyrx [107]
3 years ago
11

Density is calculated by:

Physics
2 answers:
taurus [48]3 years ago
6 0

Answer:

divide by mass and volume

Explanation:

density=mass/volume

or in symbols:p=m/v

nika2105 [10]3 years ago
5 0
Divide by mass and volume
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Cody hits up food king and uses a scale to weigh the mass of an apple. if the spring potential energy in the scale is .09 j and
Lostsunrise [7]

Answer:

oK so  here's  <u>what you should do is  add .09 and 0.6</u>

Explanation:

7 0
3 years ago
Explain the energy transformations that occur when breaking in a hybrid<br> vehicle.
KatRina [158]

it occur kinetic energy

when breaking in a hybrid

vehicle.

hope it helps

8 0
3 years ago
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A 0.150-kg lump of clay is dropped from a height of 1.15 m onto the floor. it sticks to the floor and does not bounce.
Serggg [28]
Missing question: "<span>What is the magnitude of the impulse I imparted to the clay by the floor during the impact?"

Solution:
The impulse is equal to the variation of momentum of the object: 
</span>I=\Delta p=m \Delta v
<span>where m is the mass of the object and </span>\Delta v is the variation of velocity of the object during the impact.

By using energy conservation, we can calculate the velocity of the object before the impact. In fact, the initial potential energy of the object is all converted into kinetic energy before the impact:
mgh= \frac{1}{2}mv^2
from which we find v:
v= \sqrt{2gh}= \sqrt{2 \cdot 9.81 m/s^2 \cdot 1.15 m}=4.75 m/s

This is the velocity of the object just before the impact. After the impact, the object comes to rest: this means that the variation of velocity of the object is equal to 4.75 m/s. Therefore, the impulse is

I=m \Delta v=(0.150 kg)(4.75 m/s)=0.71 Kg m s^{-1}
6 0
3 years ago
There are billions of stars in the universe how are they classified
Ilia_Sergeevich [38]

Answer: In 1926, an astronomer named Edwin Hubble decided to classify the galaxies, grouping them according to some logical scheme.

Explanation:

8 0
4 years ago
Erica (37kg ) and Danny (49kg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is movin
Semmy [17]

Answer:

2.45 m/s

Explanation:

From the law of conservation of momentum,

The total momentum before the grab = Total momentum after the grab.

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of Erica, m' = mass of Danny, u = initial velocity of Erica, u' = initial velocity of Danny, V = common velocity after garb

Make V the subject of the equation

V = (mu+m'u')/(m+m')............. Equation 2

Given: m = 37 kg, m' = 49 kg, u = 0 m/s(at the maximum height), u' = 4.3 m/s

Substitute into equation 2

V = (37×0+49×4.3)/(37+49)

V = 210.7/86

V = 2.45 m/s

Hence their speed just after the grab = 2.45 m/s

8 0
3 years ago
Read 2 more answers
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