How many traditional areas of study can chemistry be divided into

What attractive forces must be overcome when CsI is dissolvedin liquid HF?

bagirrra123 [75]

Answer:

The attractive forces must be overcome are :

Ion- ion interaction

Dipole - Dipole

Hydrogen Bonding

Explanation:

For the compound to dissolve the attractive forces existing between atoms of the compound must be reduced

CsI is ionic compound and its molecules are held together by ionic(electrostatic) force . These force must be weakened for its dissolution

Forces in HF :

1 .Hydrogen Bonding : In HF strong intermolecular Hydrogen Bonding exist between the electronegative F and Hydrogen

2. Dipole - dipole : HF is polar . So it is a permanent dipole and has dipole diople interaction

4 0

3 years ago

What is the specific heat of the following materials:

Sphinxa [80]

Answer:the sun

Explanation:leqjs

7 0

3 years ago

Solution of the Schrödinger wave equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav

kvv77 [185]

Answer :

'n' specifies → (B) The energy and average distance from the nucleus.

'l' specifies → (C) The subshell orbital shape.

'ml' specifies → (A) The orbital orientation.

Explanation :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as $m_l$ . The value of this quantum number ranges from $(-l\text{ to }+l)$ . When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as $m_s$ . The value of this is $+\frac{1}{2}$ for upward spin and $-\frac{1}{2}$ for downward spin.

As per question we conclude that,

'n' specifies → The energy and average distance from the nucleus.

'l' specifies → The subshell orbital shape.

'ml' specifies → The orbital orientation.

5 0

3 years ago

Sea water is an electrolyte. True False

antoniya [11.8K]

If you are talking about just pure regular water, the answer is false. BUT, some salts dissolved IN WATER, can act as electrolytes. But regular water, no.

8 0

3 years ago

Read 2 more answers

You are given 3.0 grams of solid sodium to react to pure water which has a molarity of 55.6 M. How many milligrams of H2 can be

serious [3.7K]

Answer:

= 15.51 mL

Explanation:

Here's is the reaction:

2HgO(s) ⇒ 2 Hg(s)+O₂(g)

In this reaction 2mol HgO = 1mol O₂

The molecular weight of HgO = 216.59g

so, 3.0g HgO = 3.0g x 1.00molHgO/216.59gHgO

= 0.0138511 molHgO

The amount of Oxygen follows:

0.0138511 molHgOx1/2= 0.00692555 mol O₂

Now, volume of 1 any gas = 22400mL

so, 0.00692555 mol O₂ x22400mLO₂/1mol O₂

= 15.513232mL O₂

4 0

3 years ago