Answer : The enthalpy change is, 7.205 KJ
Solution :
The conversions involved in this process are :
Now we have to calculate the enthalpy change.
where,
= enthalpy change = ?
m = mass of water = 10 g
= specific heat of solid water = 2.09 J/gk
= specific heat of liquid water = 4.18 J/gk
n = number of moles of water =
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
Now put all the given values in the above expression, we get
(1 KJ = 1000 J)
Therefore, the enthalpy change is, 7.205 KJ
Answer:
The answer to your question is letter D
Explanation:
Data
mass of Li = 4.5 g
mass of N₂ = 4.5 g
limiting reactant = ?
Reaction
6Li (s) + N₂ (g) ⇒ 2Li₃N
This reaction is balanced
Process
1.- Calculate the molecular mass of the reactants
Li = 7 x 6 = 42g
N = 14 x 2 = 28 g
Calculate the limiting reactant using proportions
Theoretical proportion Li / N = 42 / 28 = 1.5
Experimental proportion Li/N = 4.5/4.5 = 1
As the experimental proportion was lower than the theoretical, the limiting reactant is Lithium
2.- Calculate the theoretical yield of Li₃N
42 g of lithium -------------- 70 g of Li₃N
4.5 g of lithium ------------- x
x = (4.5 x 70) / 42
x = 315 / 42
<u> x = 7.5 %</u>
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Answer:
c
Explanation:
Change in velocity over time
The isomers are:
CH3CH2CH2CH2-Br most responsive, recause there is slightest gathering around the essential carbon iota for the nucleophile to assault.
(CH3)2CHCH2-Br second generally responsive.
.......Br
.......|
CH3CHCH2CH3 thid generally responsive.
(CH3)3C-Br slightest receptive. It is, be that as it may, energetically responsive in a Sn1 response. This is on the grounds that (CH3)3C+ is an exceptionally stable carbonium particle.