What is a claim?

How much water would need to be added to 1092 mL of a 54.7 M NaCl solution to make a 0.25 M solution?

babunello [35]

Answer:

237.8L of water would need to be added.

Explanation:

The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).

Then figure out what information you have and what is being found. In this case:

M1 = 54.7 M

V1 = 1092 mL = 1.092 L

M2 = 0.25 M

V2 = unknown

Then solve the equation for whatever you are trying to find.

M1V1=M2V2

V2=M1V1/M2

Now you need to plug everything in.

V2=(54.7M*1.091L)/0.25M

V2=238.93L

That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.

238.93L - 1.091L = 237.8L

Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.

I hope this helps. Let me know if anything is unclear.

8 0

3 years ago

A chemist is testing the quality of a wine produced by a vineyard. Which branch of chemistry might the chemist use? physical che

Phantasy [73]

Answer:

organic chemistry

Explanation:

There are many branches of chemistry. Some of them are physical chemistry, analytical chemistry, inorganic chemistry and organic chemistry.

A chemist is testing the quality of a wine produced by a vineyard. It means he will test the structure, properties, and preparation of wine. All these tests comes under organic chemistry.

Hence, the correct option is (d) "organic chemistry"

7 0

4 years ago

Read 2 more answers

How many grams of product can be produced by reacting 5.0 gram of aluminum and 22 grams of bromine? 2 Al + 3 Br2 > 2 AlBr3

Crazy boy [7]

Answer:

The mass of AlBr3 is 24.5 grams

Explanation:

Step 1: Data given

Mass of aluminium = 5.0 grams

Mass of bromine = 22.0 grams

Molar mass of aluminium = 26.98 g/mol

Molar mass of br2= 159.8 g/mol

Step 2: The balancced equation

2 Al + 3 Br2 → 2 AlBr3

Step 3: Calculate moles Al

Moles Al = mass Al / molar mass Al

Moles Al = 5.0 grams / 26.98 g/mol

Moles Al = 0.185 moles

Step 4: Calculate moles Br

Moles Br = 22.0 grams / 159.8 g/mol

Moles Br = 0.138 moles

Step 5: Calculate limiting reactant

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

Br2 is the limiting reactant. It will completely be consumed (0.0313 moles)

Al is in excess. There will react 2/3*0.138 = 0.092 moles

There will remain 0.185- 0.092 = 0.093 moles Al

Step 6: Calculate moles AlBr3

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

For 0.0313 moles Br2 we'll have 2/3*0.138 = 0.092 moles AlBr3

Step 7: Calculate mass AlBr3

Mass AlBr3 = moles * molar mass

Mass AlBr3 = 0.092 moles * 266.69 g/mol

Mass AlBr3 = 24.5 grams

The mass of AlBr3 is 24.5 grams

3 0

3 years ago

Which isotope in each pair is more stable? Why?(a) ¹⁴⁰₅₅Cs or ¹³³₅₅Cs

kiruha [24]

Among ¹⁴⁰₅₅Cs and ¹³³₅₅Cs, <u>¹³³₅₅Cs</u> is more stable.

<h3>Briefly explained</h3>

Let's review the criteria that are used to determine a stable isotope. A stable isotope will have more neutrons than protons with a neutron to proton ratio somewhere between one and 1.52 On the high atomic number, we're up to 152 at low atomic numbers were closer to one. More stable isotopes have an even number of protons. And neutrons.

And stable isotopes have their proton or neutron number equal to one of these magic numbers. So if we have season one, It has 85 Protons are start 85 neutrons And 55 protons. So we have a neutron to proton ratio of 155 for CCM 1 33. We have 78 neutrons and 55 protons for a neutron to proton ratio of 1.42. 155 is a little high for z equal to 55.

Both of these are also odd. So ¹⁴⁰₅₅Cs is the least stable. ¹³³₅₅Cs is the most stable.

Learn more about stable isotopes

brainly.com/question/2028971

#SPJ4

6 0

2 years ago

10. What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its

Sergeu [11.5K]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT = T2 - T1

ΔT = 20°C - 25°C

ΔT = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C = c

c = 4016.64 j/g.°C

4 0

3 years ago