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Eddi Din [679]
3 years ago
11

A cannon at rest fires a 32.5 kg cannonball forward at 388 m/s. After firing, the cannon recoils at 7.42 m/s. What is the mass o

f the cannon?
(Unit = kg)
Remember: right is +, left is -
Physics
1 answer:
Bond [772]3 years ago
3 0

Answer:

1700 kg

Explanation:

Let’s use conservation of momentum

32.5 * 388 = 7.42 * mc

mc = 1699.46

mc = 1700 kg

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When an ideal gas does positive work in its surroundings, which of the ga's quantities increases?
Burka [1]
I think it's B hope it helps
4 0
3 years ago
A toy cart moves with a kinetic energy of 30 J. If its speed is doubled, what is its kinetic energy?
klio [65]

Explanation:

KE is directly proportional to the square of velocity / speed.

if speed is 2 times (doubled) the KE will be

{2}^{2}

= 4 times the original KE

4 \times (30)

= 120 \: j

8 0
3 years ago
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s ​2 ​​ ) towards the Eart
Wittaler [7]

Answer:

The centripetal acceleration as a multiple of g=9.8 m/s^{2} is 1.020x10^{-3}m/s^{2}

Explanation:

The centripetal acceleration is defined as:

a = \frac{v^{2}}{r}  (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

v = \frac{2 \pi r}{T}  (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude 71.9^{\circ}. Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

\cos \theta = \frac{adjacent}{hypotenuse}

\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}} (3)

Where r_{71.9^{\circ}} is the radius at the latitude of 71.9^{\circ} and r_{e} is the radius at the equator (6.37x10^{6}m).

r_{71.9^{\circ}} can be isolated from equation 3:

r_{71.9^{\circ}} = r_{e} \cos \theta  (4)

r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})

r_{71.9^{\circ}} = 1.97x10^{6} m

Then, equation 2 can be used

v = \frac{2 \pi (1.97x10^{6} m)}{24h}

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

T = 24h . \frac{3600s}{1h} ⇒ 84600s

v = \frac{2 \pi (1.97x10^{6} m)}{84600s}

v = 146.31m/s

Finally, equation 1 can be used:

a = \frac{(146.31m/s)^{2}}{(1.97x10^{6}m)}

a = 0.010m/s^{2}

Hence, the centripetal acceleration is 0.010m/s^{2}

To given the centripetal acceleration as a multiple of g=9.8 m/s^{2}​ it is gotten:

\frac{0.010m/s^{2}}{9.8 m/s^{2}} = 1.020x10^{-3}m/s^{2}

6 0
3 years ago
Do you think that rubbing two pieces of woods together would have more or less friction than wood rubbing against smooth metal ?
jek_recluse [69]

I think rubbing two pieces of woods together will have more friction than wood rubbing against a smooth metal.

<u>Explanation:</u>

The friction offered by surfaces has a great role in deciding the ease of movement of objects along the surface.

The friction of the surface depends upon its roughness. Rough surfaces offer greater friction than smooth surfaces.

In this question wooden pieces have greater friction than that of smooth metal. So rubbing two wooden pieces together will have greater friction than rubbing a wooden piece against a smooth metal.

5 0
4 years ago
When white light is incident on a prism, which one of the resulting color components will have the lowest index of refraction?
soldi70 [24.7K]
Blue has the lowest index of refraction
3 0
3 years ago
Read 2 more answers
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