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3 years ago

What is the ionisation energy of an atom

Physics

2 answers:

V125BC [204]3 years ago

8 0

Explanation:

its the minimum amount of energy required to remove the most loosely bound electron

user100 [1]3 years ago

7 0

Answer:

Ionization energy is the amount of energy it takes for all the atoms in a molecule to lose one electron each.

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4 points

zubka84 [21]

(a) 25lx

(b) 11.11lx

<u>Explanation:</u>

Illuminance is inversely proportional to the square of the distance.

So,

$I = k\frac{1}{r^2}$

where, k is a constant

So,

(a)

If I = 100lx and r₂ = 2r Then,

$I_2 = k\frac{1}{(2r)^2}$

Dividing both the equation we get

$\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(2r)^2}{k} \\\\\frac{I_1}{I_2} = 4\\\\I_2 = \frac{I_1}{4}\\\\I_2 = \frac{100}{4} = 25lx$

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx

(b)

If I = 100lx and r₂ = 3r Then,

$I_2 = k\frac{1}{(3r)^2}$

Dividing equation 1 and 3 we get

$\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(3r)^2}{k} \\\\\frac{I_1}{I_2} = 9\\\\I_2 = \frac{I_1}{9}\\\\I_2 = \frac{100}{9} = 11.11lx$

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx

3 0

3 years ago

What happens to the body when one organ is not working properly

Vinil7 [7]

Answer: Organ failure is when a major organ stops working. Major organs all have important jobs to keep the body alive. Each organ counts on the other ones to keep the body working. If one of these organs stops working, the patient will not be able to survive without the help of very strong medicines and/or machines.

Explanation:

5 0

2 years ago

Read 2 more answers

a desktop computer and monitor together draw about 2 A of current they plug into a wall outlet that is 120 V what is the Resista

Delvig [45]

Answer:

$60 \Omega$

Explanation:

the relation between current, voltage and resistance in an electrical circuit is given by Ohm's law:

$V=IR$

where V is the voltage, I is the current and R is the resistance. In this problem, the current is I=2 A, the voltage is V=120 V, therefore we can arrange the previous equation and find the resistance:

$R=\frac{V}{I}=\frac{120 V}{2 A}=60 \Omega$