Question

a 0.125kg salt shaker sits 0.146m from the center of rotating lazy susan. if it moves 1.23m/s without sliding off what is its centripetal acceleration?(unit=m/s^2)

Answer 1

Answer:

$10.4 m/s^2$

Explanation:

For an object moving in uniform circular motion, the centripetal acceleration is given by:

$a=\frac{v^2}{r}$

where

v is the tangential speed

r is the radius of the circle

In this problem, we have:

r = 0.146 m is the radius of the circle

v = 1.23 m/s is the tangential speed

Substituting the numbers, we find:

$a=\frac{1.23^2}{0.146}=10.4 m/s^2$