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Wittaler [7]
3 years ago
7

Ronaldo runs across a soccer field, moving 10 meters north, then 8 meters west, then 4 meters south. His

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

wha is this .....................? same confusion

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What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

T=∞  (Infinite)

6 0
3 years ago
Recent findings on the topic of brain based research indicate all of the following except
Gre4nikov [31]
The answer is D, the brain actually stops growing around age 18
5 0
3 years ago
In the metric system, the appropriate unit for weight is the _____. gram newton newton/cm2 gram/cm3
Archy [21]

Answer:

Newton

Explanation:

The earth attracts every body towards its centre. The force with which the earth attracts any body towards its centre, is called its weight.

It is a vector quantity.

It always acts towards the centre of earth.

The SI unit of Newton.

4 0
3 years ago
Why do asteroids and comets differ in composition? asteroids and comets formed at different times. asteroids formed inside the f
ExtremeBDS [4]
Im not 100% sure but I beleive the answer is :Because different celestial body's form different shapes and sized of comets and meterors 
8 0
3 years ago
A steam power plant with a power output of 200 MW consumes coal at a rate of 700 tons/h. If the heating value of the coal is 40,
RUDIKE [14]

Answer:

η = 2.57%

Explanation:

Given:

Output power of the steam power plant, P(out) = 200 MW

Consumption of coal, m = 700 tons/h = (700 × 10³)/3600 kg/s= 194.44 kg/s

Heating capacity of the coal, Cv = 40000 kJ/kg

now,

Input power,  P(in) = mCv

or

P(in) =  194.44 kg/s × 40000 = 7777.77 MW

thus,

efficiency, η = P(out)/P(in) = (200 MW) / (7777.77 MW) = 0.02571

or

η = 2.57%

3 0
3 years ago
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