Answer:
new atmospheric pressure is 0.9838 ×
Pa
Explanation:
given data
height = 21.6 mm = 0.0216 m
Normal atmospheric pressure = 1.013 ✕ 10^5 Pa
density of mercury = 13.6 g/cm³
to find out
atmospheric pressure
solution
we find first height of mercury when normal pressure that is
pressure p = ρ×g×h
put here value
1.013 ×
= 13.6 × 10³ × 9.81 × h
h = 0.759 m
so change in height Δh = 0.759 - 0.0216
new height H = 0.7374 m
so new pressure = ρ×g×H
put here value
new pressure = 13.6 × 10³ × 9.81 × 0.7374
atmospheric pressure = 98380.9584
so new atmospheric pressure is 0.9838 ×
Pa
Answer:
The distance between the camera and the rock is 836.6 cm
Explanation:
A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:
cos α = adjacent/hypotenuse
cos(76.31) = 198.0/h
h = 198.0/cos(76.31)
h = 836.6 cm
Answer:
B. It is too slow to observe directly
Explanation:
They move too slow to be able to observe how they move.
I hope it helps! Have a great day!
bren~
I think it’s A not 100% sure
Answer:
Positively charged particle trajectories always follow electric field lines because the electric force on a positively charged particle is in the same direction as the electric field.
Explanation:
For any positive charge the electric field emerges radially outwards and it goes radially inwards for the negative charges.
- From the theory of electric field lines we know that they never intersect each other, either they get merged when the sources are unlike or they repel when the sources are alike. In other words the electric field lines align in the same direction as that of the field.
- So, when a positive charge is released into the an electric field they follow the direction of the field lines because they too have their field lines emerging radially outwards and hence these lines align in the direction of the field.