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2 years ago

11. Reflecting telescopes are popular because they're _______ than a refracting telescope.

2 answers:

4 0

I do not know what the school expects as an answer, but advantage of reflecting telescopes is that there is only one major reflecting surface, so it is quite easy to create a 6 or 8 inch telescope by an amateur, after adding on a prism and an eyepiece. (a microscope eyepiece could be used).
MY answer would be "easier to build". (it still takes tens of hours to grind and polish the single plane surface to a parabolic surface).

Electromagnetic waves all have the same velocity in the same medium. However, since frequencies vary widely, so do wavelengths.

lyudmila [28]2 years ago

4 0

for 11. the answer is they are D. easier to build. hope i helped (:

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A sprinter is running the 100 meter dash at a speed of 24 m/s. How long does it the sprinter to finish?

DerKrebs [107]

Answer:

4.1666666 seconds

Explanation:

100 divided by 24 will give you about 4.1666666 seconds or 4 1/6 seconds. Hope it helps!

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2 years ago

A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2

ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}$

And we need to find out the change in momentum of the body . Here ,

velocity before collision (u) = 10m/s
velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

$\sf\longrightarrow momentum (p)= mass(m) * velocity(v)$

Therefore change in momentum will be,

$\sf\longrightarrow \triangle p = mv - mu$

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

$\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\$

$\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s) \\$

$\sf\longrightarrow \Delta p = 0.1 kg * -12m/s \\$

$\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\$

7 0

1 year ago

2. Do you expect the resistance of a light bulb to remain constant as the current through it is increased and the filament goes

koban [17]

Answer:

Remember that as the temperature of an object increases, the kinetic energy of the particles inside it also increases.

So, if the temperature of a wire increases, the kinetic energy of the particles inside increases. Then when the electrons try to flow through the wire, the probability of a collision is increased (then the resistance increases). Thus, if the filament goes from red-hot to white-hot (so the temperature of the wire increases) we can conclude that the resistance that the current experiences also increases.

So no, we can not expect the resistance of the light bulb to remain constant as the filament goes from red-hot to white-hot.

3 0

2 years ago

Consider a girl that has a mass of 55.0 kg and is standing on the floor, how much supporting force does the floor have?

Zolol [24]

Answer:

at least 539 N up

Explanation:

Hope this helps!

6 0

3 years ago

Read 2 more answers

What is the relation between electric intensity dn flux

Zepler [3.9K]

The relation between the electric intensity and electric flux is that the electric flux is equal to the scalar product of electric flux intensity and vector area.

<h3>What is the relation between electric intensity and flux?</h3>

The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.

The intensity of this electric field is the number of electric field lines which are pass perpendicular to the unit element of fixed area.
The flux of this electric field is the number of electric field lines which are pass normally to the fixed area.

The electric flux can be given as,

$d\phi =\vec E \;dA\cos \theta$

When angle is zero,

$d\phi =\vec E \;dA\times1\\d\phi =\vec E \;dA$

Thus, the total flux is,

$\phi=\oint_{}^{}\vec E.d\vec A$

Thus, the relation between the electric intensity and electric flux is that the electric flux is equal to the scalar product of electric flux intensity and vector area.

Learn more about electric field here;

brainly.com/question/14372859

#SPJ4

4 0

1 year ago