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Lisa [10]
3 years ago
8

3 Na2O(aq) + 2 Al(NO3)3(aq) ----> _ Compound A + _ Compound B

Chemistry
1 answer:
Olin [163]3 years ago
7 0
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

Hope this helped!
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<h3><u>Answer;</u></h3>

Polar: IF, PCl3, IF5  

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<h3><u>Explanation:</u></h3>
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\%F=18.967\%

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Hello,

In this case, a percent composition is computed by considering the atomic mass of each element in the compound as well as the number of atoms and the molar mass of the compound. Thus, Sb2F3 has a molar mass of 300.52 g/mol, antimony has an atomic mass of 121.76 g/mol and fluorine 19.0 g/mol, therefore, the percent composition of fluorine which has three atoms with five significant figures is:

\% F=\frac{3*19.0g/mol}{300.52g/mol}*100\%\\ \\\%F=18.967\%

Best regards.

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