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3 years ago

3 Na2O(aq) + 2 Al(NO3)3(aq) ----> _ Compound A + _ Compound B

1 answer:

7 0

3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

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The sea water has 8.0x10^-1 cg of element strontium. Assuming that all strontium could be recovered, how many grams of strontium

PilotLPTM [1.2K]

984 grams of strontium will be recovered from 9.84x10^8 cubic meter of seawater.

Explanation:

From the question data given is :

volume of strontium in sea water= 9.84x10^8 cubic meter

(1 cubic metre = 1000000 ml)

so 9 .84x10^8 cubic meter

$\frac{9 .84x10^8}{1000000}$ = 984 ml.

density of sea water = 1 gram/ml

from the formula mass of strontium can be calculated.

density = $\frac{mass}{volume}$

mass = density x volume

mass = 1 x 984

= 984 grams of strontium will be recovered.

98400 centigram of strontium will be recovered.

Strontium is an alkaline earth metal and is highly reactive.

4 0

3 years ago

Which of the following is most likely to occur if the organ labeled 1 stops working correctly?

Dafna1 [17]

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6 0

3 years ago

he mineral rhodochrosite [manganese(II) carbonate, MnCO3] is a commercially important source of manganese. Write a half-reaction

valina [46]

Answer:

$MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Explanation:

Half reaction: $MnCO_{3}\rightarrow MnO_{2}$

(1) $CO_{3}$ balance: $MnCO_{3}\rightarrow MnO_{2}+HCO_{3}^{-}$

(2)H and O balance in acidic medium: $MnCO_{3}+2H_{2}O\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

(3) charge balance: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Hence balanced half-reaction: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

7 0

3 years ago

Read 2 more answers

A saturated solution of calcium hydroxide contains 1.85 g of solute in 100. mL of solution. What is its molarity

Leona [35]

Answer:

$M=0.250M$

Explanation:

Hello!

In this case, since the molarity of a solution is computed by dividing the moles of solute by the volume of solution in liters, we first need to compute the moles of solute knowing that the molar mass of calcium hydroxide is 74.1 g/mol as follows:

$n=1.85g*\frac{1mol}{74.1g}=0.0250mol$