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dybincka [34]
3 years ago
8

Find the circumference of a circle if the area is 300 square centimeters.

Mathematics
2 answers:
Blababa [14]3 years ago
8 0
The answer is:  [C]:  61.38 cm  .
_______________________________________________

Note:  A = \pi *r²

300 = (3.14) * r² ;
______________________
Divide each side by "3.14" ;

r² = 300/3.14 ; 

r² =  95.5414012738853503 ;

√r² = √(95.5414012738853503) ;

r = 9.7745281867661188048

Circumference, "C" = \pi * d ;  (d = diameter = 2*r);
 
C = 2*\pi*r ;

C = 2*(3.14)*(9.7745281867661188048)

C = 61.384037012891226094144 ; which rounds to answer choice: 
                                                             [C]:  61.38 cm  .
________________________________________________________
Nikitich [7]3 years ago
8 0

Answer:

C 61.38cm

Step-by-step explanation:

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The larger the confidence level, the wider the confidence interval gets. Choice A provides the largest such confidence level.

It's like trying to catch an elusive fish. The wider the net, the more confident that you are likely to catch the fish. The size of the net can be a sort of measure of the confidence level.

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Considering the given figure, the conjecture with the rephrased statement of proof to show the diagonals of a parallelogram bisect each other is: In parallelogram EFGH show EK is congruent to KG and F.K is congruent to KH

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The diagonals refer to the lines running between the two opposite ends of the parallelogram

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The diagonals of a parallelogram bisect each other means that the diagonals cut each other to form two equal parts such that each part is congruent to each other.

Learn more on diagonals of a parallelogram

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Using the probability concept, it is found that there is a 0.3 = 30% experimental probability that Christine will randomly choose a page that is divisible by 3.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In an experimental probability, these number of outcomes are taken from previous trials.

In this problem:

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