The spacing between sidebands is equal to 6 kHz.
<u>Given the following data:</u>
- Modulating signal = 3 kHz.
- Carrier frequency = 36 MHz.
<h3>What is a sideband?</h3>
A sideband can be defined as a band of frequencies that are lower or higher than the carrier frequency due to the modulation process. Thus, it will either be lower than or higher than the carrier frequency.
Generally, the frequency of the modulating signal is equal to the spacing between the sidebands. Therefore, a modulating signal of 3 kHz simply means that the lower sideband is <u>3 kHz</u> higher while the upper sideband is <u>3 kHz</u> lower.
Spacing = 3 kHz + 3 kHz = 6 kHz.
Read more on frequency here: brainly.com/question/3841958
Answer:
A) 209.12 GPa
B) 105.41 GPa
Explanation:
We are given;
Modulus of elasticity of the metal; E_m = 67 GPa
Modulus of elasticity of the oxide; E_f = 390 GPa
Composition of oxide particles; V_f = 44% = 0.44
A) Formula for upper bound modulus of elasticity is given as;
E = E_m(1 - V_f) + (E_f × V_f)
Plugging in the relevant values gives;
E = (67(1 - 0.44)) + (390 × 0.44)
E = 209.12 GPa
B) Formula for upper bound modulus of elasticity is given as;
E = 1/[(V_f/E_f) + (1 - V_f)/E_m]
Plugging in the relevant values;
E = 1/((0.44/390) + ((1 - 0.44)/67))
E = 105.41 GPa
Let's not take into account atmospheric pressure.
Pressure P = Pressure of oil column + Pressure of water column
= h1 . d1.g + h2.d2. g
=( 0.5 x 800 x 9.8) + ( 1x 1000x 9.8) = 3920+ 9800 = 13720
Hence guage pressure at bottom is
P= 13720 N/ m^2
