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3 years ago

At 700 K acetaldehyde decomposes in the gas phase to methane and carbon monoxide. The reaction is:

Chemistry

1 answer:

Evgen [1.6K]3 years ago

6 0

Answer:

After 1.95x10⁴ s, total pressure is 0.34 atm

Explanation:

t(s) 0 1000 3000 7000

PTotal (atm) 0.15 0.16 0.18 0.20

These are the data of the experiment, so let's make a linear regression

X | Y

0 | 0.15

1x10³ | 0.16

3x10³ | 0.18

7x10³ | 0.20

You can do this by the calculator, but let's do it manually.

Y = mx + b

m = (Y₂ - Y₁) / (X₂ - X₁)

m = 0.18 - 0.16 / 3x10³ - 1x10³

m = 0.02 / 2x10³ = 1x10⁻⁵

b = 0.15 (y-intercept, where x is 09

Y = 1x10⁻⁵ X + 0.15

Notice that in the statement, after 7000 s, pressure is 0.22 atm

1x10⁻⁵ . 1.95x10⁴ + 0.15 = 0.34atm

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Which represents the self ionization of water at 25 degrees

gayaneshka [121]

This question comes with four answer choices:

<span>A. H2O + H2O ⇄ 2H2 + O2

B. H2O + H2O⇄ H2O2 + H2

C. H2O + H2O ⇄ 4H+ + 2O2-

D. H2O + H2O ⇄ H3O+ + OH-

Answer: option </span><span>D. H2O + H2O ⇄ H3O+ + OH-

(the +sign next to H3O is a superscript, as well as the - sing next to OH)

Explanation:

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</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
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3 years ago

When 2.69 g 2.69 g of a nonelectrolyte solute is dissolved in water to make 345 mL 345 mL of solution at 26 °C, 26 °C, the solut

Gre4nikov [31]

Answer:

The molar concentration of this solution is 0.0463 mol/L

Explanation:

Step 1 : Data given

Mass of a nonelectrolyte solute = 2.69 grams

Volume of water = 345 mL = 0.345 L

Temperature = 26.0°CC = 273 + 26 = 299 K

The osmotic pressure = 863 torr

⇒ 863torr /760 = 1.13553 atm

Step 2: Calculate the molar concentration of this solution

Π = i*M*R*T

⇒with Π = the osmotic pressure = 1.13553 atm

⇒with i = the van't Hoff factor of the nonelectrolyte solute = 1

⇒with M = the molar concentration = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 299 K

1.13553 atm = 1 * M * 0.08206 L*atm/mol*K * 299 K

M = 1.13553 / (0.08206*299)

M = 0.0463 mol/L

The molar concentration of this solution is 0.0463 mol/L

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2 years ago

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2 years ago

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3 years ago

When you transferred the hot metal from the boiling water and into the calorimeter (coffee cup), if the thermometer touched the

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This is further explained below.

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