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RideAnS [48]
3 years ago
8

At 700 K acetaldehyde decomposes in the gas phase to methane and carbon monoxide. The reaction is:

Chemistry
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

After 1.95x10⁴ s, total pressure is 0.34 atm

Explanation:

t(s) 0 1000 3000 7000

PTotal (atm) 0.15 0.16 0.18 0.20

These are the data of the experiment, so let's make a linear regression

       X    |    Y

       0    |  0.15

    1x10³ |  0.16

   3x10³ |  0.18

   7x10³ |  0.20

You can do this by the calculator, but let's do it manually.

Y = mx + b

m = (Y₂ - Y₁) / (X₂ - X₁)

m =  0.18 - 0.16 / 3x10³ - 1x10³

m = 0.02 / 2x10³ = 1x10⁻⁵

b = 0.15 (y-intercept, where x is 09

Y =  1x10⁻⁵ X + 0.15

Notice that in the statement, after 7000 s, pressure is 0.22 atm

1x10⁻⁵ . 1.95x10⁴ + 0.15 = 0.34atm

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Answer:

V_1=2.49mL

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

n_{HI}=n_{HI}

One could apply the following equality in terms of molarity:

V_1M_1=V_2M_2

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL

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2 years ago
Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,
7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 )   N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)  ; Kc = 1.54e - 31

2)   N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)  ; Kc = 2.16e - 24

   upon reversing  ( 2 )  equation

     N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)   Kc = 1/2.16e - 24  

    now adding 1 and reversed equation (2)

       N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)

      N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)

   we get ,

                  N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)  Kc = 1.54e-31 × 1/2.61e - 24

       equilibrium constant of equation (3) is -

            Kc = 1.54e - 31 / 2.61e - 24

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3 years ago
Fatty acids are ________ Group of answer choices composed of carbon, hydrogen, and oxygen in a 1:2:1 ratio. composed of carbon,
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Fatty acids are composed of hydrocarbon chains and a carboxyl group.

<h3>What are Fatty acids ?</h3>

Fatty acids are the building blocks of the fat in our bodies and in the food we eat.

During digestion, the body breaks down fats into fatty acids, which can then be absorbed into the blood.

Fatty acid molecules are usually joined together in groups of three, forming a molecule called a triglyceride.

Generally, a fatty acid consists of a straight chain of an even number of carbon atoms, with hydrogen atoms along the length of the chain and at one end of the chain and a carboxyl group (―COOH) at the other end.

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Use the drop-down menus to classify the elements as alkali metals, alkaline earth metals, or transition metals.
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I attached a color-coded, labelled period table that will help to see the derivative of my responses.

3 0
3 years ago
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