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Dimas [21]
4 years ago
8

Air pressure is 1.0 · 105 N/m2, air density is 1.3 kg/m3, and the density of soft drinks is 1.0 · 103 kg/m3. If one blows carefu

lly across the top of a straw sticking up 0.100 m from the liquid in a soft drink can, it is possible to make the soft drink rise half way up the straw and stay there. How fast must the air be blown across the top of the straw?
Physics
1 answer:
natita [175]4 years ago
8 0

Answer:

v = 27.456 m/s

Explanation:

The support pressure needed of the water in the straw can be calculated by the formula

Given that,

P = r*g*h

= 1000*9.8*0.05 Pa.= 490 Pa

This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

velocity of air blown into the straw =

v = 27.456 m/s

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A space rocket accelerates uniformly from rest to 160ms^-1 upwards in 4.0s, then travels with a constant speed of 160ms^-1 for t
ivann1987 [24]

Answer:

40 ms¯².

Explanation:

To solve this problem, we shall illustrate the question with a diagram.

The attached photo gives a better understanding of the question.

From the attached photo:

Velocity (v) = 160 ms¯¹

Time (t) = 4 secs.

Acceleration (a) =?

Acceleration (a) = Velocity (v) /time (t)

a = v/t

a = 160/4

a = 40 ms¯²

Therefore, the initial acceleration of the rocket is 40 ms¯².

5 0
3 years ago
A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?
crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of 100\; \rm kg \cdot m \cdot s^{-1} each, same as that of the 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}. Assumption: all four balls are moving in the same direction.

Explanation:

The momentum p of an object is equal to the product of its mass m and its velocity v.

Momentum of a 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}:

p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}.

Similarly:

  • Momentum of the ball in choice a: 100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice b: 5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice c: 2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.

Hence the conclusion that these balls have the same momentum.

7 0
3 years ago
What is the wavelength of a 2.50-kilohertz sound
Alexxx [7]
The formula v=fλ can be used here.

326=2500*λ

Note the 2500 as 2.5kHz is 2.5 thousand Hz.

λ = 326/2500
= 0.1304m = 0.130m
3 0
3 years ago
Which of the following is not a part of a wave?
Alisiya [41]
B is the correct answer
y=Asin(wt-kx)
A=amplitude
f=frequency
x=wavelength
since refraction is not on the wave formula,then option B is the correct answer
5 0
3 years ago
Read 2 more answers
An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 18
Salsk061 [2.6K]

Explanation:

Given that,

Potential difference, V = 412 V

Magnitude of magnetic field, B = 188 mT

(a) The potential energy of electron is balanced by its kinetic energy as :

eV=\dfrac{1}{2}mv^2

v is speed of the electron

v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s

(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :

r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m

Hence, this is the required solution.                                

7 0
3 years ago
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