Answer:
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Explanation:
This problem uses the relationship between Kb and the the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:
<span>
Kb = KaKb
</span><span>1.00 x 10^-14 = 7.2 x 10^-4(x)
</span><span>x = 1.39 x 10^-11
</span><span>
We now need to calculate the [OH¯] using the Kb expression:
</span>1.39 x 10^-11 = x^2 / (0.30 - x)
<span>
The denominator can be neglected. </span><span>Thus, x is 3.73 x 10^-6.
</span><span>
pOH = -log 3.73 x 10^-6 = 5.43
p</span><span>H = 14-5.43 = 8.57</span>
Answer:
A solid has the molecules tightly packed together and are held in a fixed pattern.
A liquid has molecules that are packed together in a random fashion and can move freely.
A gas has molecules that are widely separated and randomly move and collide.
Explanation:
Correct answer to this question is c. water evaporating