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4 years ago

G Write an equation showing what happens when AgNO3 is added, and explain why the equilibrium shifts

Chemistry

1 answer:

Afina-wow [57]4 years ago

8 0

Answer:

$\mathbf{AgNO_3+Cl^- \to AgCl_s + NO^{3-}}$

Explanation:

The addition of AgNO3 to the system Cl⁻ react with result into the formation a precipitate of AgNO3, as such the reactant concentration decreases.

$\mathbf{AgNO_3+Cl^- \to AgCl_s + NO^{3-}}$

Suppose the concentration of a given substance is present in an equilibrium system is changed without a change in any of the other conditions, then, by le chatelier's principle, the position of equilibrium will move to decrease the concentration of the added substances. In order to relieve this constraint, the equilibrium will shift to the right favouring the forward reaction.

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The cell theory was construted by

NeTakaya

Answer:

Matthias Jakob Schleiden

Explanation:

The cell was initially discovered by Robert Hooke, but Schleiden developed the theory.

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4 years ago

from the equation 2PbO + C = 2Pb + CO2, detemine which one is reactant is oxidised and which is reduced.

ss7ja [257]

Answer:

Explanation:

C is oxidised because C up to C+4

PbO is reduced because PbO from Pb2+ down to Pb0

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3 years ago

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Another gas was used for many years to float transportation balloons.

Alja [10]

Another gas that was used to fill balloons was hydrogen. The reason why hydrogen is not used today is because it use to cause many fires when it was used to fill balloons up.

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6 0

4 years ago

Pleaseee helpppppppp

ahrayia [7]

Answer:

Potassium

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:

The atom having only one electron its outermost shell must belong to an element in group one of the periodic table.

Having noted that, we proceed to find out what element in group one that has the atom just described in the question.

That atom must belong to an element in the fourth period. The only group 1 element in the fourth period is potassium.

The electron configuration of potassium is;

1s2 2s2 2p6 3s2 3p6 4s1

6 0

3 years ago

The half-life for beta decay of strontium-90 is 28.8 years. a milk sample is found to contain 10.3 ppm strontium-90. how many ye

ryzh [129]

Answer : The correct answer is 96.68 yrs

Radioactivity Decay :

it is a process in which a nucleus of unstable atom emit energy in form of radiations like alpha particle , beta particle etc .

Radioactive decay follows first order kinetics , so its rate , rate constant , amount o isotopes can be calculated using first order equations .

The first order equation for radioactive decay can be expressed as :

$ln \frac{N}{N_0} = - k*t$ ----------- equation (1)

Where : N = amount of radioisotope after time "t"

N₀ = Initial amount of radioisotope

k = decay constant and t = time

Following steps can be used to find time :

1) To find deacy constant :

Decay constant can be calculated using half life . Decay constant and half life can be related as :

$T _\frac{1}{2} = \frac{ln2}{k}$ ---------equation (2)

Given : Half life of Strontium -90 = 28.8 years

Plugging value of $T_\frac{1}{2}$ in above formula (equation 2) :

$28.8 yrs = \frac{ln 2}{ k }$

Multiply both side by k

$28.8 yrs * k = \frac{ln 2 }{k} * k$

Dividing both side by 28.8 yrs

$\frac{28.8 yrs * k}{28.8 yrs} = \frac{ln 2}{28.8 yrs}$

(ln 2 = 0.693 )

k = 0.0241 yrs⁻¹

Step 2 : To find time :

Given : N₀ = 10.3 ppm N = 1.0 ppm k = 0.0241 yrs⁻¹

Plugging these value in equation (1) as :

$ln (\frac{1.0 ppm}{10.3 ppm} ) = - 0.0241 yrs^-^1 * t$

$ln (0.0971 ) = -0.0241 yrs ^-^1 * t$

(ln 0.0971 = - 2.33 )

Dividing both side by - 0.0241 yrs⁻¹

$\frac{-2.33}{-0.0241 yrs^-^1} = \frac{-0.0241 yrs^-^1 * t}{-0.0241 yrs^-^1}$

t = 96.68 yrs

Hence the concentration of Strontium-90 will drop from 10.3 ppm to 1.0 ppm is 96.68 yrs

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3 years ago

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