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FromTheMoon [43]
3 years ago
15

If a vector A has components A. 0, and Ay -0, then the magnitude of the vector is negative. Select one: True False

Physics
2 answers:
Dima020 [189]3 years ago
8 0

Answer:

False

Explanation:

The magnitude of any vector is given by,

||A||=\sqrt{A_x^2+A_y^2}

The magnitude of anything is never negative. It can be even seen from the formula that the components are squared. A squared value can never be negative. Even if the component is negative the square will be always positive.

So, magnitude of the vector is <u>not</u> negative.

Anika [276]3 years ago
7 0

Answer:

The given statement is false.

Explanation:

For a given vector \overrightarrow{A}=A_{x}\widehat{i}+A_{y}\widehat{j}

The magnitude is given by |A|=\sqrt{A_{x}^{2}+A_{y}^{2}}

As we can see that the quantity on the right side of equation is always positive since square root of a quantity is always positive thus we conclude that the magnitude of any vector and hence vector A is always positive.

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3 years ago
A 6 N and a 10 N force act on an object. The moment arm of the 6 N force is 0.2 m. If the 10 N force produces five times the tor
Levart [38]

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