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Greeley [361]
3 years ago
13

What must a system owner do, once the threshold leak rate has been exceeded on any low-pressure system using an ozone-depleting

refiigerant?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

A procedure according to the norms.

Explanation:

If possible, proceed to fix the leak in no more than 30 days from the moment it was discovered.

Otherwise, during the first 30 days develop a planification to backfit the leak or, if needed, retire the appliance. This should be executed within one year.

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a snail can move approximately 0.30 meters per minute.How many meters can the snail cover in 15 minutes ?
hichkok12 [17]
Sometimes if you have the word per, you need to multiply. In this problem, they are asking you to find the amount of meters a snail can travel per minute.They are giving you the amount of minutes, so in this case you multiply 15 times 0.30. The answer is 4.5 meters.

8 0
3 years ago
Estimate the total number of bacteria and other prokaryotes in the biosphere of the earth. (assume the bacteria are found to a d
Fofino [41]
Since the Earth is almost spherical in shape, we are actually to find first the volume of the spherical segment at a depth of 1,000 m. The radius of the Earth is 6,371,000 meters. The volume of a spherical segment is:

V = 1/3*πh²(3r - h)
Substituting the values and making sure the units is in mm,
V = 1/3*π(1000 m * 1000 mm/1 m)²[3(6,371,000 m * 1000 mm/1 m) - (1000 m * 1000 mm/1 m)]
V = 2×10²² mm³

Thus, the total amount of bacteria is:

2×10²² mm³ * 100 bacteria/1 mm³ = 2×10²⁴ bacteria
7 0
4 years ago
Multiple-Concept Example 6 reveiws the principles that play a role in this problem. A nuclear power reactor generates 2.3 x 109
r-ruslan [8.4K]

Answer:

change in mass = 2.41*10^{8}kg

Explanation:

The change in the mass can be computed by using the relation

E=\Delta mc^2\\\Delta m=\frac{E}{c^2}(1)

That is, the energy liberated comes from the mass of the nuclear fuel. The energy generated in one year is

E=Pt=2.3*10^{9}\frac{J}{s}*1 year*\frac{365.25 day}{1 year}*\frac{24h}{1 day}*\frac{3600s}{1h}=7.25*10^{16}J

Hence, by replacing in the equation (1) you have  (c=3*10^{8}m/s)

\Delta m=\frac{7.25*10^{16}J}{3*10^{8}\frac{m}{s}}=2.41*10^{8}kg

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point to
Brut [27]

Answer:

It would point up.

Explanation:

Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.

Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.

So, the compass would point up.

7 0
3 years ago
Two particles collide, one of which was initially moving and the other initially at rest. Is it possible for both particles to b
solmaris [256]

Answer:

Not possible

Explanation:

Unless there's some extra external force to keep both particles at rest after the collision, the momentum must be conserved before and after the collision.

So before the collision, 1 particle is at rest, 1 not ->  total momentum is non-zero

After the collision, both particles are at rest -> total momentum is zero which is different from before.

Therefore this is not possible.

4 0
3 years ago
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