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Greeley [361]
3 years ago
13

What must a system owner do, once the threshold leak rate has been exceeded on any low-pressure system using an ozone-depleting

refiigerant?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

A procedure according to the norms.

Explanation:

If possible, proceed to fix the leak in no more than 30 days from the moment it was discovered.

Otherwise, during the first 30 days develop a planification to backfit the leak or, if needed, retire the appliance. This should be executed within one year.

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PRESS THE PHOTO NEED HELP!!! 30 POINTS
olasank [31]

1:-

\\ \sf\longmapsto cos\Theta=\dfrac{B}{H}

\\ \sf\longmapsto cos\Theta=\dfrac{4}{5}

2:-

\\ \sf\longmapsto tan\Theta=\dfrac{P}{B}

\\ \sf\longmapsto Tan\Theta=\dfrac{3}{4}

Key Notes:-

  • P denotes to Perpendicular.
  • B denotes to Base.
  • H denotes to Hypotenuse.
8 0
3 years ago
Read 2 more answers
You are making cookies that call for 3 tablespoons of molasses, but you are having trouble measuring out the thick, syrupy liqui
Andreyy89
You could heat the syrup, grease the spoon with shortening, because if you do, then the molasses won't stick when you pour it out of the spoon into the batter.
3 0
4 years ago
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Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = \frac{kQ_{1}Q_{2} }{r^{2} }

F= \frac{K(Q/2)(3Q/4)}{r^{2} }

how \frac{KQ^{2} }{r^{2} } = 0.42

Then

F = \frac{0.42*3}{8}

F = 0.1575 N

3 0
3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
Alexxx [7]

Explanation:

It is given that,

Radius of the circular orbit, r=0.53\times 10^{-10}\ m  

Speed of the electron, v=2.2\times 10^6\ m/s

Mass of the electron, m=9.1\times 10^{-31}\ kg

(a) The force acting on the electron is centripetal force. Its formula is given by :

F=\dfrac{mv^2}{r}

F=\dfrac{9.1\times 10^{-31}\times (2.2\times 10^6)^2}{0.53\times 10^{-10}}  

F=8.31\times 10^{-8}\ N

(b) The centripetal acceleration of the electron is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(2.2\times 10^6)^2}{0.53\times 10^{-10}}

a=9.13\times 10^{22}\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
1. What outdoor activities do you prefer? Why? 2. What outdoor activities are you interested in, but have never tried?​
DochEvi [55]

Answer:

My favorate activies is skateboareding, and I prerfer outdoor actives.

Explanation:

3 0
3 years ago
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