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Troyanec [42]
3 years ago
5

Ice fishermen sit on top of frozen lakes in the winter and catch fish in the liquid water below through holes cut in the ice she

et. The fact that the lake doesn't freeze solid is a good thing for those fish who live there and for the hungry fishermen. In this problem we will investigate how long it takes for this sheet of ice to form and why the lake doesn't freeze solid during the winter. The water on the surface of the lake only starts to freeze when the air temperature is below the freezing temperature of water.
Why does the ice only form on the surface and not throughout the entire volume of the lake?
Physics
1 answer:
melomori [17]3 years ago
8 0

Answer:

This is because below 4°c, water unlike other materials becomes less dense when it's temperature is further lowered.

Explanation:

Due to the unusual nature of water; at about 4°c, the behavior of the density of water in relation to its temperature reverses. This means that water becomes less dense as it becomes colder below 4°c. The colder parts therefore floats to the top of the water body while the warmer part sinks allowing the top to freeze and the remaining body below to remain in its liquid state.

The freezing of the top of the lake alone protects the remaining depth of water from freezing by acting as an insulator and preventing further heat loss from the water to the ambient space. If this had not been the case, and water froze all through, marine lives will freeze to death and it will be more difficult to melt the ice come the next summer.

This behavior is due to the hydrogen bonding of the water molecules.

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A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative
Liula [17]

Question is missing. Found on google:

a) What are the components of the acceleration of the fish?  

(b) What is the direction of its acceleration with respect to unit vector î?

(c) If the fish maintains constant acceleration, where is it at t = 30.0 s?

(a) (0.73, -0.47) m/s^2

The initial velocity of the fish is

u=(4.00 i + 1.00 j) m/s

while the final velocity is

v=(15.0 i - 6.00 j) m/s

Initial and final velocity are related by the following suvat equation:

v=u+at

where

a is the acceleration

t is the time

The time in this case is t = 15.0 s, so we can use the previous equation to find the acceleration, separating the components:

v_x = u_x + a_x t\\a_x = \frac{v_x-u_x}{t}=\frac{15.0-4.00}{15.0}=0.73 m/s^2

v_y = u_y + a_y t\\a_y = \frac{v_y-u_y}{t}=\frac{-6.00-1.00}{15.0}=-0.47 m/s^2

(b) -32.8^{\circ}

The direction of the acceleration vector with respect to i can be found by using the formula

\theta = tan^{-1}(\frac{a_y}{a_x})

where

a_x is the horizontal  component of the acceleration

a_y is the vertical component of the acceleration

From part a), we have

a_x = 0.73 m/s^2

a_y = -0.47 m/s^2

Substituting,

\theta = tan^{-1}(\frac{-0.47}{0.73})=-32.8^{\circ}

(c) r=(460.5 i - 185.1 j )m

The initial position of the fish is

r_0 = (12.0 i -3.60 j) m

The generic position r at time t is given by

r= r_0 + ut + \frac{1}{2}at^2

where

u=(4.00 i + 1.00 j) m/s is the initial velocity

a=(0.73 i -0.47 j) m/s^2 is the acceleration

Substituting t = 30.0 s, we find the final position of the fish. Separating each component:

r_x =12.0 + (4.00)(30) + \frac{1}{2}(0.73)(30)^2=460.5 m\\r_y = -3.60 + (1.00)(30) + \frac{1}{2}(-0.47)(30)^2=-185.1 m

So the final position is

r=(460.5 i - 185.1 j )m

4 0
3 years ago
IF object A has more mass than object B, does object A contain more matter? Explain
lukranit [14]
Have you ever heard this phrase, "What weighs more, a ton of feathers, or a ton of lead?" The answer is, they weigh the same, however the ton of feathers takes up more space than the ton of lead. So to answer your question, the answer is yes, and no. Depending on what the substance is will determine your answer. I hope that i helped.
7 0
3 years ago
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prohojiy [21]
Hope this helps you.

3 0
4 years ago
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Answer:

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Explanation:

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