Answer:
60km/hr west
Explanation:
When you are dealing with velocity you always name the direction its going in
Answer:
a
Explanation:
I think its a its speed increases.....
To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be

Where
A = Surface area
e = Emissivity that characterizes the emitting properties of the surface
= Universal constant called the Stefan-Boltzmann constant 
T = Absolute temperature
The total heat loss would be then





Therefore the net rate of heat loss from the body by radiation is 155.29J
Answer:
Soup kitchen, on site, and 2 last ones
Explanation: