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fenix001 [56]
4 years ago
8

How is the solubility of a substance usually described?

Chemistry
1 answer:
d1i1m1o1n [39]4 years ago
8 0
The solubility of a substance is a measurement that describes how much solute <span>dissolves in a given amount of solvent.

Hope this helps!</span>
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An unknown gas is found to diffuse through a porous membrane 4.11 times more slowly than h2 what is the molecular weight of the
kirill [66]
To answer this question, you need to know <span>Graham's Law of Effusion/Diffusion formula. In this formula, the rate of diffusion/effusion would be influenced by the mass. As the molecule has bigger mass, the rate should be slower because it will be harder to pass the membrane. The calculation should be:</span>
<span>Rate 1 / Rate 2 = √[M2/M1] 
</span>4.11/1= √[M2/2] 
M2=33.78 g/mol

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4 years ago
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If I have 5,000g of sodium, how much sodium sulfide can be made?
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HELP ASAP!
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8 0
3 years ago
Describe the similarities and differences between herbivores,carnivore,and omnivores​
vredina [299]

Answer:

Herbivores only eat plants . Remember HERBS are PLANTS.

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Omnivores eat MEAT & PLANTS.

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3 0
3 years ago
How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=200 K

Putting value in the given equation:

\frac{nRT}{P} =V

V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}

V= 1.1214 mL

Learn more about the ideal gas here:

brainly.com/question/27691721

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2 years ago
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