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m_a_m_a [10]
3 years ago
7

____ Are subatomic particles found in the nucleus and carry positive electrical charge.

Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
7 0
C. Protons
Protons are subatomic particles found in the nucleus and carry positive electrical charge.
Lorico [155]3 years ago
3 0

Answer:

C

Explanation:

there's no need to rush just calm down baby!!!

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Do centromeres divide at anaphase i or ii
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How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.
Westkost [7]

Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

5 0
3 years ago
Identify the molecule that is not a compound.
aev [14]
Compound is a molecule made of atoms from different elements. Allcompounds are molecules, but not allmolecules are compounds. Hydrogen gas (H2) is a molecule, but not a compound because it is made of only one element.
4 0
2 years ago
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