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klasskru [66]
4 years ago
12

A scientist wants to determine how temperature affects photosynthesis? He sets up a controlled experiment in which he places sma

ll plants acquired from an aquarium store into 3 separate test tubes. He pours 20 ml of cold water into one test tube, 20 mL of room temperature water into the second test tube, and 20 mL of warm water into the third test tube. He covers each test tube with a small latex balloon and measures the circumference of each balloon after 2 days. What is the test (independent0 variable?
Chemistry
1 answer:
IgorC [24]4 years ago
4 0

Answer:

Independent variable: DIFFERENT TEMPERATURE

Explanation:

The independent variable of an experiment is the variable that the experimenter changes or manipulates in order to effect an outcome or response in the measured variable/dependent variable.

In this experiment, a scientist wants to determine how temperature affects photosynthesis. He sets up the experiment by adding 20ml of water at different temperatures to three test tubes. Hence, the independent or experimental variable is the DIFFERENT TEMPERATURES GIVEN TO EACH PLANTS IN THE TEST TUBE because it is what the experimenter changes in order to effect a measurable outcome i.e. oxygen released in each balloon as a result of photosynthesis, which is the dependent variable

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Nitrogen monoxide and ozone react to form nitrogen dioxide and oxygen, like this:
andre [41]

Answer:

The pressure of O2 will increase. Shift to the right.

The pressure of O3 will increase . Dhift to the left

Explanation:

<em>The perturbations are:</em>

<em>The temperature is lowered. The pressure of O2 will</em>

<em>The temperature is raised. The pressure of O3 will:</em>

We can Apply LeCh's principle and see the heat, ΔH, as a product of the reaction:

NO(g) + O3(g) → NO2(g) + O2(g) + ΔH

If temperature is lowered, the system will <em>shift to the right </em>in order to produce more heat doing:

The pressure of O2 will increase

In the other way, if temperature is raised, the system will <em>shift to the left</em> in order to decrease the amount of heat produced.

The pressure of O3 will increase

3 0
3 years ago
draw the major product, including regiochemistry, for the reaction of hex-3-yne with one equivalent of HCl. Is it an E configura
ANTONII [103]

Answer:

The reaction of hex-3-yne with one equivalent of HCl Is an Anti addition, see in the drawing the major product.

Explanation:

The mechanism of the reaction proceeds through a carbocation, formed in the most substituted carbon of the triple bond,  in this case it is indistinct because the triple bond is in the central carbons. Therefore, it is a regioselective reaction that follows Markovnikov's rule, adding the halogen to the more substituted carbon of the alkyne.

The anti addition consists in the addition of two substituents on opposite sides of a triple bond, which gives it greater stability.

3 0
3 years ago
what type of recording do you think would be the best method of submitting evidence to a crime lab? why?
Margaret [11]

The type of recording that is the best and most useful method of submitting evidence to a crime lab is by videography.

The videography is the type of evidence that pretty much contains everything that can be get from a recording because it has both the visual aspects and the audio aspects of the crime scene. It can be said that the videography represents the ultimate type of notes.

4 0
3 years ago
Read 2 more answers
Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

Answer:

a. 0.5 mol

b. 1.5 mol

c. 0.67

Explanation:

Fe3+ + SCN- -----> [FeSCN]2+

a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium

b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

c. KC =  0.5/(0.5*1.5) =  0.67

3 0
3 years ago
Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature, a chemist finds tha
stepan [7]

The question is incomplete, here is the complete question:

Iron(III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 5.4 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, iron, and water at equilibrium has the following composition:

Compound        Amount

   Fe_2O_3         3.54 g

      H_2             3.63 g

      Fe             2.37 g

     H_2O           2.13 g

Calculate the value of the equilibrium constant for this reaction. Round your answer to 2 significant digits

<u>Answer:</u> The value of equilibrium constant for the given reaction is 2.8\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 3.63 g

Molar mass of hydrogen gas = 2 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

\text{Molarity of hydrogen gas}=\frac{3.63}{2\times 5.4}\\\\\text{Molarity of hydrogen gas}=0.336M

  • <u>For water:</u>

Given mass of water = 2.13 g

Molar mass of water = 18 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

\text{Molarity of water}=\frac{2.13}{18\times 5.4}\\\\\text{Molarity of water}=0.0219M

The given chemical equation follows:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of K_c for above equation follows:

K_c=\frac{[H_2O]^3}{[H_2]^3}

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression. So, the concentration of iron and iron (III) oxide is not present in equilibrium constant expression.

Putting values in above equation, we get:

K_c=\frac{(0.0219)^3}{(0.336)^3}\\\\K_c=2.77\times 10^{-4}

Hence, the value of equilibrium constant for the given reaction is 2.8\times 10^{-4}

7 0
3 years ago
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