Question

A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.130 M AuNO 3 solution at 25 °C. The gold wire is connected to the positive end of a potentiometer, and the S.C.E. is connected to the negative end of the potentiometer. What is the half‑reaction that occurs at the Au electrode? Include physical states.

Answer 1

Answer:

The half reaction occurring at this electrode will be given as:

$Au^++e^-\rightarrow Au$

Explanation:

In electrochemical cell reduction occurs at anode.

But the gold wire is connected to the positive terminal of the battery which means that gold wire will act as a cathode nad reduction will take place

The half reaction occurring at this electrode will be given as:

$Au^++e^-\rightarrow Au$