Answer:
a. 27 m/s2
b. 2.75:1
Explanation:
a.
Since it is assumed that the race car starts from rest, initial velocity, u = 0 m/s
At the end of 402 m, distance, s = 402 m; and
Final velocity, v = 330 m/h
Converting this to m/s,
m/s
Using the equation of motion



b.
If acceleration due to gravity is taken as 9.8 m/s2, then

Explanation:
Given that,
Wavelength of light, 
Angle, 
We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

n is 1 here
d is slit spacing

So, the slit spacing is
.
The formula to solve this is (.80)^3 X 6 and the answer would be 3.1 feet. That is how high the ball will rebound after its third bounce. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
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For constant fore the impulse could be increased by increasing the time for the force.