Is this a true or false question?
Answer:
Explanation:
Let the velocity after first collision be v₁ and v₂ of car A and B . car A will bounce back .
velocity of approach = 1.5 - 0 = 1.5
velocity of separation = v₁ + v₂
coefficient of restitution = velocity of separation / velocity of approach
.8 = v₁ + v₂ / 1.5
v₁ + v₂ = 1.2
applying law of conservation of momentum
m x 1.5 + 0 = mv₂ - mv₁
1.5 = v₂ - v₁
adding two equation
2 v ₂= 2.7
v₂ = 1.35 m /s
v₁ = - .15 m / s
During second collision , B will collide with stationary A . Same process will apply in this case also. Let velocity of B and A after collision be v₃ and v₄.
For second collision ,
coefficient of restitution = velocity of separation / velocity of approach
.5 = v₃ + v₄ / 1.35
v₃ + v₄ = .675
applying law of conservation of momentum
m x 1.35 + 0 = mv₄ - mv₃
1.35 = v₄ - v₃
adding two equation
2 v ₄= 2.025
v₄ = 1.0125 m /s
v₃ = - 0 .3375 m / s
The maximum displacement angle of the bob is 13⁰.
The given parameters;
- <em>Length of the pendulum, L = 1.25 m</em>
- <em>Initial velocity of the bob, v = 0.8 m/s</em>
The maximum displacement of the bob is calculated by applying the principle of conservation of energy;
The maximum displacement angle is calculated as follows;
Thus, the maximum displacement angle of the bob is 13⁰.
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Answer:
option c
Explanation:
K.E=1/2mv(squared)
K.E=1/2x900x80x80
K.E=450x6400=2880000J
convert to KJ=2880000/1000=2880KJ
