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qaws [65]
4 years ago
6

In a positive correlation, when one variable increases, the other variable

Physics
2 answers:
Ulleksa [173]4 years ago
7 0

Answer:the other variable increases

Explanation:

alexdok [17]4 years ago
5 0

Answer:

Positive correlation is a relationship between two variables in which both variables move in tandem—that is, in the same direction. A positive correlation exists when one variable decreases as the other variable decreases, or one variable increases while the other increases.

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The spaces in bones are filled with a soft connective tissues called what
BaLLatris [955]
Answer: cartilage
There are plenty different types of tissue found in bones such as bone marrow, endosteum, nerves, blood vessels, and of course cartilage.
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4 years ago
If a biker starts at rest and accelerates to 15 m/s in 7.5 seconds, what is his<br> acceleration? *
sergeinik [125]

Answer:

2 m/s^2

Explanation:

from the question

v=15 m/s

t=7.5

a=?

from the first equation of motion

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration

t=time

from the question (u) will be zero because the body started at rest

v=u+at

15=(0)+a×7.5

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6 0
3 years ago
Percy Spencer was an American engineer and, while working for Raytheon, was building magnetrons for radar sets. One day, he was
Sladkaya [172]

Answer:

the answer is d

Explanation:

4 0
3 years ago
Read 2 more answers
A moving walkway has a speed of 0.9 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of
Leona [35]
B or .2 East is the correct answer
3 0
3 years ago
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4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.
mojhsa [17]

Answer:

102 m upwards.

Explanation:

Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
2 years ago
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