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3 years ago

Could someone explain what oxidation numbers are and what these questions are asking of me?

Chemistry

1 answer:

Oxana [17]3 years ago

6 0

The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation of an atom in a chemical compound.

<u>Explanation:</u>

The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. 1. The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element. The oxidation number of simple ions is equal to the charge on the ion.

The oxidation number of a mono atomic ion equals the charge of the ion. The oxidation number of H is +1, but it is -1 in when combined with less electro negative elements. The oxidation number of O in compounds is usually -2, but it is -1 in peroxides. The oxidation number of a Group 1 element in a compound is +1.

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When the above equation is balanced the coefficients in order are

Softa [21]

The reaction is as follow,

Ca(OH)₂ + Al₂(SO₄)₃   → CaSO₄ + Al(OH)₃

Ca are balance on both sides,

There are 2 Al at left side and one at right so, multiply Al(OH)₃ by 2 to balance,
So,
Ca(OH)₂ + Al₂(SO₄)₃   → CaSO₄ + 2 Al(OH)₃

Now, Ca and Al are balanced, now balance SO₄, which is 3 at left hand side and one at right hand side, so multiply CaSO₄ on right side by 3, so,

Ca(OH)₂ + Al₂(SO₄)₃   → 3 CaSO₄ +  2 Al(OH)₃

Again Ca got imbalance, so multiply Ca(OH)₂ by 3 to balance Ca, So,

3 Ca(OH)₂ + Al₂(SO₄)₃   → 3 CaSO₄ +  2 Al(OH)₃

The Equation is balance now with respect to every element.

Result:
The Ratio is 3 : 1 : 3 : 2, so, Option-G is correct.

4 0

3 years ago

Elements in the same column of the periodic table of the elements all

Andre45 [30]

Answer:

Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Explanation:

6 0

3 years ago

Read 2 more answers

If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?

Maksim231197 [3]

The answer is A. 12.2% BaO

Below is the solution as to how the answer was generated:

Let:

25.8g = mass of solute

212g = mass solution

Equation:

% = (mass of solute / mass solution) x 100

Substitute the given values to the equation:

% = (25.8 / 212) x 100

% = 0.122 x 100

= 12.2%

5 0

3 years ago

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A 6.0-L flask contains a mixture of methane (CH₄), argon, and helium at 45°C and 1.75 atm. If the mole fractions of helium and a

ikadub [295]

Given information,

A 6.0-L flask contains a mixture of methane (CH4), argon, and helium at 45degreeC and 1.75 atm.

The mole fractions of helium and argon are 0.25 and 0.35 respectively.

Calculate the number of methane molecules are present,

$\mathrm{V}=6.0 \mathrm{~L}=0.006 \mathrm{~m}^{3} ; \mathrm{T}=45^{0} \mathrm{C}=318.15 \mathrm{~K} ; \mathrm{P}=1.75 \mathrm{~atm}=177318.75 \mathrm{~Pa}$

Mole fraction of methane $=1-0.25-0.35=0.4$

$\begin{aligned}\mathrm{P}_{\text {methane }} &=\mathrm{P} \times \text { mole fraction }=177318.75 \mathrm{~Pa} \times 0.4=70927.5 \mathrm{~Pa} \\\mathrm{PV} &=\mathrm{nRT}=(\mathrm{NRT}) / \mathrm{N}_{\mathrm{A}} \\\mathrm{N} &=\left(\mathrm{pVN}_{\mathrm{A}}\right) /(\mathrm{RT}) \\\mathrm{N} &=\frac{70927.5 \times 0.006 \times 6.022 \times 10^{23}}{8.314 \times 318.15} \\&=9.69 \times 10^{22} \text { molecules }\end{aligned}$$$

The mole fraction is one of several methods for expressing the solution's concentration. A unit of concentration is a mole fraction. The mole fraction, which is denoted by "X," is a unit of measurement for the ratio of solute to solvent in a solution.

The mole fraction is not temperature-dependent.

Calculating the mole fraction does not need knowledge of the phase's density.

The mole fraction of an ideal gas mixture is expressed by the mixture's partial pressure to total pressure ratio.

Learn more about mole fraction brainly.com/question/8076655

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7 0

1 year ago

What are the final materials of a reaction called? Where are they located in an<br> equation?

fredd [130]

Answer:

Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

4 0

3 years ago