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ruslelena [56]
3 years ago
12

Object A has a temperature of 287 Kelvin, object B has a temperature of 374 Kelvin. In what direction will thermal energy flow?

Chemistry
2 answers:
Mashcka [7]3 years ago
6 0
Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.
IgorLugansk [536]3 years ago
6 0

Explanation:

Internal energy which is present within the molecules of an object due to the kinetic energy of its particles is known as thermal energy.

Thermal energy will always flow an object with high temperature towards an object with low temperature only when both the objects are placed in contact with each other.

For example, when object A has a temperature of 287 Kelvin, and object B has a temperature of 374 Kelvin. Then thermal energy will from from object B to object A.

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How does the average velocity of molecules in a high-temperature gas compare to the average velocity of molecules of the same ga
IrinaK [193]

Answer:lower temp molecules act slower so they come closer together and heated molecules are more spaced out that is why when you put an ice cube in a hot pan the ice melts and turns into a liquid due to heat the molecules space out

Explanation:

8 0
3 years ago
What is the percent composition of hydrogen if a sample is found to contain 7 grams of hydrogen, 32 grams of nitrogen, and 7 gra
nata0808 [166]

<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %

<u>Explanation:</u>

We are given:

Mass of hydrogen = 7 grams

Mass of nitrogen = 32 grams

Mass of carbon = 7 grams

Total mass of the sample = 7 + 32 + 7 = 46 grams

To calculate the percentage composition of hydrogen in sample, we use the equation:

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of sample}}\times 100

Mass of sample = 46 g

Mass of hydrogen = 7 g

Putting values in above equation, we get:

\%\text{ composition of hydrogen}=\frac{7g}{46g}\times 100=15.22\%

Hence, the percent composition of hydrogen in the sample is 15.22 %

6 0
3 years ago
a cylinder with a movable piston contains 250 cm3 air at 10°C. if the pressure is kept constant, at what temperature would you e
soldi70 [24.7K]

Answer:

T₂ = 169.89 K

Explanation:

Given data:

Initial volume = 250 cm³

Initial temperature = 10°C (10+273.15 K = 283.15 K)

Final temperature = ?

Final volume = 150 cm³

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 283.15 K × 150 cm³ /  250 cm³

T₂ = 42472.5 K. cm³  / 250 cm³

T₂ = 169.89 K

5 0
3 years ago
What law is known as the law of action-<br> reaction?
Molodets [167]

Law of Action and Reaction mean "To every action there is equal and opposite reaction.

Explanation:

It is Newtons third law which explained few  things such as :-

1. The nature of the forces between the two interacting objects.

2. According to this law , the force that is exerted from Object-1 to Object-2 is said to be equal in magnitude and opposite to the direction to the force exerted to object 2 upon object 1.

3. Eaxmple - As we push against the wall - Action , the wall in return opposes equal force to resist the pressure of the hand - Reaction.

6 0
3 years ago
What mass of NaCl is dissolved in 150 g of water in a .050<br> msolution?
mart [117]

Answer:

0.4383 g

Explanation:

Molality is defined as the moles of the solute present in 1 kg of the solvent.

It is represented by 'm'.

Thus,  

Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}

Given that:

Mass of solvent, water = 150 g = 0.15 kg ( 1 g = 0.001 g )

Molality = 0.050 m

So,

0.050=\frac {Moles\ of\ the\ solute}{0.15}

Moles = 0.050\times 0.15\ mol= 0.0075\ mol

Molar mass of NaCl = 58.44 g/mol

Mass = Moles*Molar mass = 0.0075\times 58.44\ g = 0.4383 g

6 0
4 years ago
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