A gas because if you freeze water, it turns into a shape as where gas can’t be frozen
The complete reaction along with intermediates is given below, with each step highlighted in different color.
Step 1: In this step an acidic proton at alpha position is abstracted from lactone moiety and corresponding enolate is formed, which is resonance stabilized. Both structures are shown. In this case LDA (<span>Lithium diisopropylamide) acts as a base.
</span>
Step 2: The enolate formed attacks on Methyl Iodide, as Iodide being greater in size is a good leaving group and alpha methyl moiety is generated.
Step 3: This step is acid catalyzed Bromination. Bromine is added at alpha position.
Step 4: This is elimination reaction and is according to <span>Hofmann's Rule. Here less substituted alkene is generated.</span>
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em><u>Proton</u></em><em><u>.</u></em>
<em><u>Additional</u></em><em><u> </u></em><em><u>Information</u></em><em><u>:</u></em>
<em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>three</u></em><em><u> </u></em><em><u>types</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>subatomic</u></em><em><u> </u></em><em><u>particles</u></em><em><u>.</u></em><em><u> </u></em><em><u>They</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>
- <em><u>Proton</u></em>
- <em><u>Electron</u></em>
- <em><u>Neutron</u></em>
<em><u>Proton</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>positively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u>,</u></em><em><u>Electron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>negatively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>Neutron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em><em><u>less</u></em><em><u>.</u></em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
<span>Bases can both take up hydrogen ions and release hydroxide ions. This differs from an acid, which releases a hydrogen ion. Combining acids and bases can produce a lot of heat during the reaction. If the acid and base are of the same strength, the mixture will be neutralized.</span>
Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.
Explanation:
density
ρ
=
Mass
Volume
, and thus units of
g
⋅
m
L
−
1
are reasonable.
For this problem:
17.4
⋅
m
L
×
0.798
⋅
g
⋅
m
L
−
1
≅
14
⋅
g
but A i supposed?