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3 years ago

I WILL GIVE BRAINLIEST!!!

Physics

1 answer:

astra-53 [7]3 years ago

7 0

Answer:

is that high school work??? cause I don't know it and I'm about to go to high school

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Diffraction occurs for all types of waves, including sound waves. High-frequency sound from a distant source with wavelength 9.0

Nataliya [291]

Answer:

The minimum distance is $y = 892.48 \ cm$

Explanation:

The diagram of this set up is shown on the first uploaded image

From the question we are told that

The wavelength is $\lambda = 9.00\ cm$

The width of the slit is $d = 12.0 cm$

The distance of the microphone is $L = 8.0 \ m = 8*100 = 800 \ cm$

Generally the diffraction minima in a single slit is mathematically represented as

$dsin \theta = m \lambda$

Where m is the order of diffraction which is 1 in this question

So making $\theta$ the subject

$\theta = sin^{-1} [\frac{m * \lambda }{ d} ]$

$\theta = sin^{-1} [\frac{1 * 9.00}{12.00} ]$

$\theta =0.84 \ rad$

Now from the diagram

$y = 800 tan 0.84$

$y = 800* (1.1156)$

$y = 892.48 \ cm$

4 0

3 years ago

Three point charges are placed at distances of d , 2 d , and 3 d from a point P. The particle that is 2 d away from P has a char

mel-nik [20]

Answer:

at d the charge will be 3q and at 3d it will be 9q

Explanation:

for V=Vp-V2d

V=KQ/d=K*6q/2d=3kq/d for potential to 2d at 6q be zero the Vp will equal 3kq/d; hence at d, Q=3q and at 3d, Q=9q

7 0

3 years ago

How can you protect yourself from lightning?

julsineya [31]

Stay inside when theres lightning or try not to be the tallest object in a wide open space

6 0

3 years ago

Read 2 more answers

Where in your house do you find radio waves

WITCHER [35]

theyre found from your microwave

4 0

3 years ago

Read 2 more answers

Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an

Mumz [18]

Answer:

The hoop

Explanation:

We need to define the moment of inertia of the different objects, that is,

DISK:

$I_{disk} = \frac{1}{2} mR^2$

HOOP:

$I_{hoop} = mR^2$

SOLID SPHERE:

$I_{ss} = \frac{2}{5}mR^2$

HOLLOW SPHERE

$I_{hs} = \frac{2}{3}mR^2$

If we have the same acceleration for a Torque applied, then

$mR^2>\frac{2}{3}mR^2>\frac{1}{2} mR^2>\frac{2}{5}mR^2$

$I_{hoop}>I_{hs} >I_{disk}>I_{ss}$

The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

4 0

3 years ago