Question

A girl is standing on a trampoline. Her mass is 65 kg and she is able to jump 3 m. What is the spring constant for the trampoline? (logger pro?)

Answer 1

Answer:

k = 212.55 newton per meter

Explanation:

A girl is standing on a trampoline. Her mass is 65 kg and she is able to jump 3 meters.

We have to find the spring constant.

Since by Hooke's law,

F = -kx

Where F = force applied by the spring

k = spring constant

x = displacement

And we know force applied by the spring will be equal to the weight of the girl.

So, F = mg

Therefore, (-mg) = -kx

65×(9.81) = k×(3)

k = $\frac{(65)(9.81)}{3}$

k = 212.55 N per meter

Therefore, spring constant of the spring is 212.55 Newton per meter.