Answer:
final temperature is 364.32 K
mass of air is 0.5423 kg
Explanation:
given data
pressure p1 = 380 kPa
volume v1 = 0.120 m³
temperature = 20°C = 20 + 273 = 293 K
pressure p2 = 3450 kPa
volume v2 = 5% increase
to find out
final temperature and the mass
solution
we consider here ideal gas
so equation is
p1v1 / t1 = p2v2/t2
put here all value and find t2
and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³
so
t2 = p2v2/ p1v1 × t1
t2 = (450 × 0.126) / (380 × 0.120) × 293
t2 = 364.32 K
so final temperature is 364.32 K
and
mass = p2v2 / Rt2
here R gas constant is 0.287 kJ/kg.K
so
mass = (450 × 0.126) / (0.287 × 364.32 )
mass = 0.5423
so mass of air is 0.5423 kg
C is a non-metal and so is O. So the answer is CO
Answer:
v2 = 65 m/s
the speed of the water leaving the nozzle is 65 m/s
Explanation:
Given;
Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle
Initial speed v1 = 0.65 m/s
diameter d1 = 3.0 cm
diameter (nozzle) d2 = 0.3 cm
The volumetric flow rates in both the hose and the nozzle are the same.
V1 = V2 ........1
Volumetric flow rate V = cross sectional area × speed of flow
V = Av
Area = (πd^2)/4
V = v(πd^2)/4 ....2
Substituting equation 2 to 1;
v1(πd1^2)/4 = v2(πd2^2)/4
v1d1^2 = v2d2^2
v2 = (v1d1^2)/d2^2
Substituting the given values;
v2 = (0.65 × 3^2)/0.3^2
v2 = 65 m/s
the speed of the water leaving the nozzle is 65 m/s
Answer:
- Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0
- Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]
- Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .
- Acceleration is defined as the rate of change of velocity. We know :
- Plug the values & then simplify !
- The acceleration of the jeep is 0.2 m/s²
- Plug the values & then simplify !
- The distance covered by the jeep is 9000 m .
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Answer:
Longest wavelength, lowest intensity
Explanation:
