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2 years ago

7

A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is

a resultant force of 3 N on the wire due to the interaction of the current and field, what is the magnetic field strength

1 answer:

LenaWriter [7]2 years ago

8 0

Answer:

0.2

Explanation:

F= BIL sin©

3= B×10×1.5 sin90

B=3/15

B= 0.2

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