Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf

Where, B = magnetic field
l = length
v = velocity
Put the value into the formula


We need to calculate the induced current


Put the value into the formula


(b). We need to calculate the power dissipated through the resistor
Using formula of power

Put the value into the formula


Hence, The induced current and the power dissipated through the resistor are 0.5 mA and
.
Given that
Velocity of missile (v) = 20 m/s ,
Angle of missile (Θ) = 53°
Determine , Vertical component = v sin Θ
= 20 sin 53°
= 15.97 m/s
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
Answer:
Acceleration will be 
Explanation:
We have given initial speed of the car is 70 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So 
It is given that car stops in 12 sec
So final speed of the car v = 0 m/sec
Time t = 12 sec
From first equation of motion v = u+at
So 
( negative sign indicates that speed of the car will constantly decrease )
Answer:
wave length is 1.2m
Explanation:
since formula of wave length is v/f
v(speed of sound in air at stp is 300ms^-1)
f(frequency 250hertz)
then wave length is 300÷250 which give 1.2m