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DiKsa [7]
3 years ago
14

A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:

factor the polynomial into (x+3) and (x-5) STEP 2: x+3=0 and x-5=0 STEP 3: x=3 and x=-5 A) the student did not make any mistakes, the solution is correct B) in step 3 C) in step 1 D) in step 2
Physics
1 answer:
AveGali [126]3 years ago
3 0
B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5
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cestrela7 [59]

Answer:

T_{2}=278.80 K

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(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}.

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\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}

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Combining this equation with the first equation we have:

(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}

(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}

Now, we just need to solve this equation for T₂.

T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}

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Answer:

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