1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
3 years ago
14

A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:

factor the polynomial into (x+3) and (x-5) STEP 2: x+3=0 and x-5=0 STEP 3: x=3 and x=-5 A) the student did not make any mistakes, the solution is correct B) in step 3 C) in step 1 D) in step 2
Physics
1 answer:
AveGali [126]3 years ago
3 0
B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5
You might be interested in
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
Plz, Help!!
SIZIF [17.4K]
C is the first & the second question is A
7 0
3 years ago
Read 2 more answers
When changing a tire sized 195/75 R15 to a 5 percent lower profile, the correct tire size would be _____
valentinak56 [21]

Answer and explanation:

When you are changing a car tire, the most important thing is to keep the total diameter as equal as possible.

The total car tire diameter can be calculated as:

D_{tot orig}=\frac{195 \cdot 75}{2540 \cdot 2}+15''=26.5''

The profile of this tire is 75 (the higher/taller relation), therefore a 5 percent lower profile would be:

pr=0.95·75=71.25

The problem is that the profiles are normalized and the nearest profile available is 70.

If we take a theorical tire with a profile of 71.25:

D_{tot orig}=D_{new}\\\frac{195 \cdot 75}{2540 \cdot 2}+15''=\frac{X \cdot 71.25}{2540 \cdot 2}+15''\\X=205.26

The theorical tire size should be 205/71 R15.

If we look for a real tire size, we should look for a tire with a diameter nearest to 26.5'' and a profile of 70.

The best option for real tire size is: Tire 225/70 R14 (wheel diameter of 26.4'') or 205/70 R15 (wheel diameter of 26.3'').

3 0
4 years ago
Does time stand still in space
ruslelena [56]

Answer:

It's mostly known that time stops moving in a black hole, as for space, its known the spacetime changes over time. A black hole in such a state is essentially stationary. So for my research, time does not stand still in space unless were taking about black holes.

Explanation:

6 0
3 years ago
Read 2 more answers
Other questions:
  • A rectangular aluminum bar (~1.52.1 cm in cross section) and a circular steel rod (~1 cm in radius) are each subjected to an axi
    8·1 answer
  • The wavelength of some green light is 530.0 nm. what is the frequency of this green light?
    9·1 answer
  • you lift a 30 N crate 2 meters onto a shelf. it takes you 5 seconds to accomplish this. how much gravitional potential energy do
    12·1 answer
  • A crate is given a push across a horizontal surface. The crate has a mass m, the push gives it an initial speed of 1.90 m/s, and
    5·1 answer
  • Discuss how a photon (aka the light particle) can be affected by gravity despite being massless.
    10·1 answer
  • Which statement is true about the element shown here? A) This element tends to gain electrons to become stable. B) This element
    14·2 answers
  • Which element is most likely to carry electric current easily?
    15·1 answer
  • A student is planning an investigation on the properties of different types of matter. What would be the best method to find the
    8·2 answers
  • Can I have some help
    14·1 answer
  • Which crash caused a greater change in motion for the satellite explains why and how? Write at least 1 paragraph and use vocab.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!