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DiKsa [7]
3 years ago
14

A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:

factor the polynomial into (x+3) and (x-5) STEP 2: x+3=0 and x-5=0 STEP 3: x=3 and x=-5 A) the student did not make any mistakes, the solution is correct B) in step 3 C) in step 1 D) in step 2
Physics
1 answer:
AveGali [126]3 years ago
3 0
B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5
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Answer:

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We have the following data:

m₁ = mass of trailing car = 400 kg

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The final speed of the leading car is given by the following formula:

v_2=\frac{2m_1}{m_1+m_2}u_1-\frac{m_1-m_2}{m_1+m_2}u_2\\\\v_2=\frac{(2)(400\ kg)}{400\ kg+400\ kg}(6.4\ m/s)-\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(3.5\ m/s)

<u>v₂ = 6.4 m/s</u>

The final speed of the leading car is given by the following formula:

v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\\\v_1=\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(6.4\ m/s)+\frac{(2)(400\ kg)}{400\ kg+400\ kg}(3.5\ m/s)

<u>v₁ = 3.5 m/s</u>

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