Answer:
T_warm = 47.22 C
Explanation:
Using energy balance for the system:
m_1*h_1 + m_2*h_2 = m_3*h3 ... Eq1
h_i = c_p. T_i ... Eq 2
m_1 + m_2 = m_3 ... steady flow system (Eq 3)
Substitute Eq 2 and Eq3 in Eq1
m_3 = 0.8 + 1 = 1.8 kg/s
(0.8)*(4.18)*( 348-273) + (1)*(4.18)*( 298-273) = 1.8 * 4.18 *T_3
T_3 = 355.3 / (1.8*4.18) = 47.22 C
C, I took the test already.
Answer:
d) The elastic potential energy is at its maximum when the velocity of the ball is a maximum.
Explanation:
The total energy in a simple harmonic motion is the sum of its kinetic and potential energy.
Option D is false because when the velocity of the ball is at its maximum, the kinetic energy is maximum, and when the kinetic energy is at maximum, the elastic potential energy will be at minimum.
Answer:
The answer is below
Explanation:
a) To solve this problem, we are going to use the smith chart. After entering the value of Zo = 200 ohm and ZL = (50 − j25) Ω, this give us
, the intersection between
and the SWR line gives:

b) Also, we get:
